Solving Pair of Linear Equations using Substitution Method

The video tutorial explains how to solve a pair of linear equations using the substitution method. It begins with an introduction to the method, followed by an example using two linear equations. The tutorial demonstrates solving the equations by substituting either X or Y, showing that both approaches yield the same results. The conclusion emphasizes that both the elimination and substitution methods can solve linear equations effectively.

What is the main focus of the substitution method introduced in the session?

• Solving quadratic equations

• Solving pair of linear equations

• Finding the roots of a polynomial

• Calculating the determinant of a matrix

When substituting X from equation #2 into equation #1, what is the expression for X?

• X = 4 - Y

• X = 2 + Y

• X = 3Y

• X = Y - 2

After substituting X in equation #1, what is the resulting equation to solve for Y?

• Y = 4

• 2Y = 4

• 2Y = 2

• Y = 2

What is the value of Y when substituting X in equation #1?

• Y = 0

• Y = 1

• Y = 2

• Y = 3

What is the expression for Y when substituting Y from equation #2 into equation #1?

• Y = 2X

• Y = X - 2

• Y = 4 - X

• Y = X + 2

What is the value of X when substituting Y in equation #1?

• X = 4

• X = 3

• X = 2

• X = 1

What conclusion is drawn about the substitution and elimination methods?

• They are not suitable for solving linear equations

• They yield the same results for the given equations

• They are only applicable to quadratic equations

• They yield different results