Circular Motion Example 1

The video tutorial explains the concept of circular motion, focusing on a car traveling at a constant speed of 60 km/h around a circular path with a radius of 100 meters. It covers the tangential and normal components of velocity and acceleration vectors, and provides mathematical equations to calculate the magnitude of acceleration. The tutorial emphasizes the importance of using SI units and demonstrates the calculation of acceleration as 2.78 m/s², showing that it is purely in the normal direction due to the constant speed of the car.

What is the speed of the car in meters per second when converted from 60 kilometers per hour?

• 18 m/s

• 15 m/s

• 20 m/s

• 16.67 m/s

In circular motion, how is the velocity vector oriented with respect to the path?

• Perpendicular to the path

• Tangential to the path

• Parallel to the radius

• Radial to the path

What are the components of the acceleration vector in circular motion?

• Only tangential

• Radial and axial

• Tangential and normal

• Only normal

What is the formula for the normal component of acceleration in circular motion?

• R^2 / v

• v^2 / R

• v / R

• v * R

What is the derivative of speed with respect to time when the speed is constant?

• Equal to acceleration

• Equal to velocity

• Zero

• Equal to speed

What is the magnitude of the car's acceleration in the normal direction?

• 3.5 m/s²

• 2.78 m/s²

• 1.5 m/s²

• 4.0 m/s²

Why is there no tangential component of acceleration in this scenario?

• Because the speed is increasing

• Because the speed is constant

• Because the radius is changing

• Because the path is not circular