Curvilinear motion example 2

The video tutorial addresses a challenging curve linear motion problem involving a ball bearing constrained to a circular path by a slider moving at a constant velocity. The instructor explains the problem, generalizes the solution, and discusses velocity and acceleration components. The solution is derived using trigonometry and vector analysis, emphasizing the importance of expressing acceleration in different ways. The tutorial concludes with a discussion of alternative methods to solve the problem, such as using angular velocities and accelerations.

What is the initial problem presented in the video?

• Finding the velocity of a ball bearing

• Determining the path of a slider

• Calculating the magnitude of acceleration

• Measuring the distance traveled by a ball

How is the velocity vector of the ball bearing described?

• As a single vector

• As a decreasing function

• As a constant value

• As a combination of horizontal and vertical components

What trigonometric function is used to relate the velocity components?

• Sine

• Tangent

• Secant

• Cosine

What are the two components of the acceleration vector?

• Static and dynamic

• Horizontal and vertical

• Linear and angular

• Tangential and normal

Why is the acceleration in the Y direction zero?

• Because the velocity is increasing

• Because the velocity is constant

• Because the path is linear

• Because the angle is 90 degrees

What is the relationship between the normal acceleration and velocity?

• Normal acceleration is the square of velocity divided by radius

• Normal acceleration is the product of velocity and radius

• Normal acceleration is the sum of velocity and radius

• Normal acceleration is the difference between velocity and radius

How is the acceleration in the X direction calculated?

• By multiplying normal acceleration by cosine of the angle

• By subtracting normal acceleration from cosine of the angle

• By using the sine of the angle

• By dividing normal acceleration by cosine of the angle

What is the final expression for the magnitude of acceleration?

• VY squared minus R cosine Theta

• VY squared times R cosine Theta

• VY squared over R cosine Theta

• VY squared plus R cosine Theta

What alternative method is mentioned for solving the problem?

• Using graphical representation

• Applying calculus

• Calculating angular velocities and accelerations

• Using linear equations

What is the final calculated magnitude of acceleration?

• 0.5 meters per second squared

• 1 meter per second squared

• 2 meters per second squared

• 1.5 meters per second squared