Calculating Sound Intensity and Energy Transfer in Physics

This tutorial focuses on solving physics problems related to sound intensity. It begins with calculating the intensity of sound from a 500-watt speaker at a distance of 4 meters. The tutorial then explores how much energy is absorbed by the eardrum per minute, given its surface area. It also covers the calculation of power emitted by a sound source using intensity and distance. Finally, the tutorial explains the inverse square law and its application in determining sound intensity at different distances.

What is the formula for calculating sound intensity?

• Intensity = Area / Power

• Intensity = Power / Area

• Intensity = Area x Power

• Intensity = Power x Area

If a speaker emits 500 watts of power, what is the intensity of sound 4 meters away?

• 3.75 watts per square meter

• 4.98 watts per square meter

• 2.49 watts per square meter

• 1.25 watts per square meter

How do you convert 60 square millimeters to square meters?

• 60 / 1000

• 60 x 1000^2

• 60 x 1000

• 60 / 1000^2

What is the energy absorbed by the eardrum per minute if the intensity is 2.49 watts per square meter?

• 0.896 joules

• 0.000896 joules

• 0.0896 joules

• 0.00896 joules

What is the power emitted by a source if the intensity is 3 x 10^-6 watts per square meter at 10 meters?

• 3.77 milliwatts

• 3.77 watts

• 0.377 milliwatts

• 0.0377 watts

According to the inverse square law, what happens to intensity if the distance is doubled?

• It becomes half

• It remains the same

• It becomes one-fourth

• It doubles

If the distance from a sound source is tripled, what happens to the intensity?

• It becomes one-third

• It remains the same

• It triples

• It becomes one-ninth

What is the new intensity if the original intensity is 100 watts per square meter at 3 meters and the distance is increased to 6 meters?

• 100 watts per square meter

• 50 watts per square meter

• 25 watts per square meter

• 75 watts per square meter

Using the inverse square law, how do you calculate the ratio of two intensities?

• r1^2 / r2^2

• r2 / r1

• r2^2 / r1^2

• r1 / r2

If the intensity is 100 watts per square meter at 3 meters, what is the intensity at 9 meters?

• 50 watts per square meter

• 11.1 watts per square meter

• 75 watts per square meter

• 33.3 watts per square meter