Vector Displacement and Trigonometry Concepts

Vector Displacement and Trigonometry Concepts

Assessment

Interactive Video

Mathematics, Physics, Science

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers vector basics, including breaking vectors into horizontal and vertical components. It then applies this knowledge to a real-life problem involving a car's path, calculating displacement using Pythagoras' theorem, and determining the bearing of the displacement using trigonometry.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the two components into which a vector can be broken down?

Scalar and Vector

Horizontal and Vertical

Magnitude and Direction

Diagonal and Perpendicular

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If vector W is the sum of vectors U and V, what does this imply about U and V?

U and V are parallel

U and V are the components of W

U and V are perpendicular

U and V are equal in magnitude

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the car's path problem, what is the direction of the first vector representing the car's movement?

West

East

South

North

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the magnitude of a vector using Pythagoras' theorem?

Divide the components and take the square root

Subtract the components and take the square root

Multiply the components and take the square root

Add the squares of the components and take the square root

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the magnitude of the car's displacement in the given problem?

25 km

15 km

70 km

50 km

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the bearing of a vector?

The length of the vector

The angle it makes with the horizontal

The angle it makes with the vertical

The direction it travels in

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the bearing of the net displacement calculated?

Using the sine rule

Using the cosine rule

Using trigonometry with opposite and adjacent sides

Using the law of tangents

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