Anti-Markovnikov Hydrohalogenation Concepts

Anti-Markovnikov Hydrohalogenation Concepts

Assessment

Interactive Video

Chemistry, Science, Biology

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains the anti-Markovnikov hydrohalogenation reaction, focusing on its regiospecificity and the role of peroxides in shifting the reaction from Markovnikov to anti-Markovnikov. It details the mechanism, including initiation and propagation steps, and emphasizes the stability of alkyl radicals. The tutorial concludes with the formation of the anti-Markovnikov product and a summary of the mechanism.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main difference between Markovnikov and anti-Markovnikov hydrohalogenation?

The temperature at which the reaction is conducted

The type of halogen used

The solvent in which the reaction occurs

The position where the halogen adds to the carbon chain

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What role do peroxides play in anti-Markovnikov hydrohalogenation?

They change the solvent polarity

They initiate the formation of free radicals

They act as a catalyst for the reaction

They increase the reaction temperature

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

During the initiation step, what type of bond cleavage occurs in peroxides?

Heterolytic bond cleavage

Ionic bond cleavage

Homolytic bond cleavage

Covalent bond formation

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is formed when a hydroxyl radical reacts with HBr?

A bromine radical and water

A bromine ion and hydrogen radical

A hydrogen radical and bromine

A hydroxide ion and bromine radical

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the propagation step, why does the bromine radical add to the less substituted carbon?

To increase the reaction rate

To decrease the reaction temperature

To form a more stable alkyl radical

To form a more stable carbocation

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the remaining pi electron after the bromine radical forms a bond with the carbon?

It forms a bond with another bromine radical

It is lost as heat

It is transferred to the secondary carbon

It forms a new pi bond

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the final propagation step in the anti-Markovnikov mechanism?

Formation of a primary alkyl radical

Formation of a secondary alkyl radical

Formation of an alkyl bromide

Formation of a hydroxyl radical

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