Understanding KB Calculations and ICE Charts

Understanding KB Calculations and ICE Charts

Assessment

Interactive Video

Chemistry, Science, Mathematics

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to calculate the base dissociation constant (Kb) using a given pH value. It starts by comparing the problem to a previous Ka calculation, then describes the reaction of a base with water, leading to the formation of BH+ and O-. The tutorial demonstrates how to use pH to find the concentration of O- and sets up an ICE chart to determine initial and final concentrations. Finally, it calculates Kb using these values and concludes with a summary of the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main difference between calculating Ka and KB in this problem?

The use of pH instead of pOH

The use of pOH instead of pH

The use of a base instead of an acid

The use of a different temperature

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the reaction of a base with water, what does the base receive?

A neutron

A hydroxide ion (OH-)

An electron

A proton (H+)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between pH and pOH?

They add up to 14

They are equal

They multiply to 14

They subtract to 7

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the concentration of O- calculated from pOH?

10 to the power of negative pH

10 to the power of pH

10 to the power of negative pOH

10 to the power of pOH

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the 'E' in the ICE chart stand for?

Equilibrium

Energy

Endothermic

Exothermic

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can water be ignored in the ICE chart for this reaction?

It is a solid

It is a liquid and does not affect the K value

It is a catalyst

It is a gas

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final concentration of O- used in the KB calculation?

1.58 * 10^-3

1.58 * 10^4

1.58 * 10^3

1.58 * 10^-4

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