Algebraic Equations and Word Problems

Mr. Woolley introduces Lesson 23, emphasizing the importance of equations in solving real-world problems. He provides a detailed walkthrough of solving algebraic equations, including examples and word problems related to phone bills. The video concludes with instructions for students to complete their work on Schoology.

What is the main focus of Mr. Woolley's lesson?

• Geometry and shapes

• Algebraic equations and real-world applications

• History of mathematics

• Basic arithmetic operations

What is the first step in solving the equation 2/3x - 4 = 20?

• Add 4 to both sides

• Divide both sides by 2/3

• Multiply both sides by 3

• Subtract 4 from both sides

How do you handle division by a fraction in an equation?

• Divide by the reciprocal of the fraction

• Add the fraction to both sides

• Subtract the fraction from both sides

• Multiply by the reciprocal of the fraction

In the equation -1 + x = 8, what operation is used to isolate x?

• Subtract 1 from both sides

• Add 1 to both sides

• Multiply both sides by 2

• Divide both sides by 2

What is the solution to the equation 5x + 14 = -7?

• x = 3.2

• x = 4.2

• x = -3.2

• x = -4.2

How is Bob's phone bill modeled in the word problem?

• 0.10m + 5 = 22

• 0.05m - 10 = 22

• 0.10m - 5 = 22

• 0.05m + 10 = 22

How many minutes did Bob use in July according to the word problem?

• 280 minutes

• 220 minutes

• 240 minutes

• 260 minutes

What is the monthly cost of Kim's new phone plan?

• $28.00

• $30.00

• $24.50

• $22.50

How much does Kim save per month with her new phone plan?

• $3.00

• $3.50

• $4.00

• $4.50

What was the cost of Kim's old phone plan per month?

• $28.00

• $24.50

• $30.00

• $22.50