Reaction Mechanisms and Rate Laws

Reaction Mechanisms and Rate Laws

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

This chemistry lecture covers reaction mechanisms and rate laws, explaining how reactions occur in steps and the role of intermediates. It discusses the rate determining step and how to derive rate laws from reaction mechanisms. The lecture includes example problems to illustrate these concepts.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it unlikely for three reactant particles to collide simultaneously to form a product?

Because simultaneous collisions are rare.

Because they are too small to collide.

Because they are in different phases.

Because they repel each other.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is an intermediate in a reaction mechanism?

A byproduct that is not used in the reaction.

A catalyst that speeds up the reaction.

A product that is formed and consumed during the reaction.

A reactant that starts the reaction.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What determines the speed of a reaction in a multi-step mechanism?

The step with the highest energy.

The slowest step.

The step with the most reactants.

The fastest step.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can we verify if a proposed reaction mechanism is correct?

By checking if the products are colorful.

By comparing the derived rate law with experimental data.

By ensuring the reactants are in the same phase.

By measuring the temperature change.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the rate constant 'K' in a rate law?

It determines the color of the reactants.

It is a measure of the reaction's speed.

It indicates the reaction's equilibrium.

It shows the reaction's temperature.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should be done if an intermediate appears in the rate-determining step?

Ignore it in the rate law.

Substitute it with the concentration of starting reactants.

Use it as a catalyst.

Replace it with a product.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the given problem, why can't N2O2 be used directly in the rate law?

Because it is a reactant.

Because it is an intermediate.

Because it is a catalyst.

Because it is a product.

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?