Newton's Law of Cooling Concepts

Newton's Law of Cooling Concepts

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains a problem involving Newton's Law of Cooling, where the temperature of a hot body decreases from 100°C to 70°C in an environment of 20°C. The instructor guides through the process of solving the problem using the cooling formula, identifying constants, and calculating the temperature after 2 hours. The solution involves understanding the relationship between the body and surrounding temperatures, and applying logarithmic functions to find the constants C and K.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial temperature of the hot body in the given problem?

50 degrees centigrade

100 degrees centigrade

70 degrees centigrade

20 degrees centigrade

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to Newton's Law of Cooling, what is the temperature of the surrounding environment?

20 degrees centigrade

50 degrees centigrade

70 degrees centigrade

100 degrees centigrade

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate the temperature of the body over time?

theta = theta_naught + C * e^(-KT)

theta = theta_naught - C * e^(-KT)

theta = theta_naught + C * e^(KT)

theta = theta_naught - C * e^(KT)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the constant C found in the problem?

50

20

100

80

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the constant C in the formula?

It represents the initial temperature

It represents the surrounding temperature

It is the final temperature

It is a scaling factor for the exponential term

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant K determined in the problem?

By using the final temperature

By using the initial temperature

By using the surrounding temperature

By using the temperature change over one hour

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for K in terms of logarithms?

K = -log(8/5)

K = log(5/8)

K = -log(5/8)

K = log(8/5)

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