Vertex and Parabola Properties

Vertex and Parabola Properties

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

This video tutorial explains how to find the maximum or minimum value of a quadratic function. It begins by simplifying the function through combining like terms. The direction of the parabola is determined by the sign of the coefficient of x squared. The vertex's x value is calculated using the formula -b/2a. Finally, the x value is plugged back into the function to find the minimum or maximum value, depending on the parabola's direction.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the maximum or minimum value of a quadratic function?

Substitute the x-value into the function

Combine similar terms in the function

Find the x-value of the vertex

Determine the direction of the parabola

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the direction in which a parabola opens?

By checking the sign of the vertex

By checking the sign of the coefficient of x

By checking the sign of the constant term

By checking the sign of the coefficient of x squared

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the coefficient of x squared is positive, in which direction does the parabola open?

To the right

To the left

Upward

Downward

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What formula is used to find the x-value of the vertex in a quadratic function?

2a/b

b/2a

-b/2a

-b/a

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the function f(x) = 2x^2 + 5x + 4, what are the values of a and b?

a = 2, b = 5

a = 5, b = 2

a = 4, b = 5

a = 2, b = 4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After finding the x-value of the vertex, what is the next step?

Substitute the x-value into the function

Combine similar terms

Determine the direction of the parabola

Find the y-intercept

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the minimum value of the function f(x) = 2x^2 + 5x + 4 when x = -1.25?

1.25

-1.25

0.875

-0.875

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