Chlorine Compounds and Oxidation States

The video tutorial explains how to determine the oxidation number of chromium in the ion Cr(NH3)4Cl2+. It begins by discussing the concept of oxidation numbers and their significance in ions. The tutorial then walks through the process of calculating the oxidation number for chromium, setting up a mathematical expression, and solving it to find that the oxidation state of chromium is +3. The video concludes with a brief summary of the steps taken.

What is the charge on the ion in the compound Cr(NH3)4Cl2+?

• +1

• +2

• 0

• -1

What is the oxidation number of NH3 in the compound?

• +1

• +3

• 0

• -1

What is the oxidation number of chlorine in the compound Cr(NH3)4Cl2+?

• +2

• -1

• 0

• +1

How many chlorine atoms are present in the compound Cr(NH3)4Cl2+?

• 4

• 1

• 2

• 3

Which group does chlorine belong to in the periodic table?

• Group 15

• Group 18

• Group 17

• Group 16

What is the mathematical expression used to find the oxidation number of chromium in the compound?

• x - 4 = 0

• x + 4 = 0

• x - 2 = 1

• x + 2 = 1

What is the oxidation state of chromium in Cr(NH3)4Cl2+?

• +4

• +2

• +5

• +3