Understanding Aqueous Reactions and Ionic Equations

Understanding Aqueous Reactions and Ionic Equations

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to write and balance net ionic equations, using the example of KOH and BaCl2. It begins by balancing the molecular equation, ensuring all elements are accounted for. The tutorial then discusses the solubility of compounds, using a solubility chart to confirm the solubility of barium hydroxide. Finally, it analyzes the ions present in the reaction, concluding that no reaction occurs as all ions remain unchanged in solution.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Write the ionic equation

Determine the solubility of compounds

Balance the molecular equation

Identify the spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the chlorines in the reaction between KOH and BaCl2?

Add a coefficient of 2 in front of KOH

Add a coefficient of 2 in front of Ba(OH)2

Add a coefficient of 2 in front of KCl

Add a coefficient of 2 in front of BaCl2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of potassium hydroxide in the reaction?

Liquid

Aqueous

Solid

Gas

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is barium hydroxide considered soluble in water?

It is insoluble

It is a strong base

It is a strong acid

It forms a precipitate

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of a solubility chart in this context?

To determine the reaction rate

To identify the products

To check the solubility of compounds

To balance the equation

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the 's' symbol indicate on a solubility chart?

Suspended

Soluble

Solid

Saturated

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean when all compounds in a reaction are aqueous?

A precipitate forms

No reaction occurs

The reaction is endothermic

The reaction is exothermic

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