Balancing Double Displacement Reactions

Balancing Double Displacement Reactions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Sophia Harris

FREE Resource

This video tutorial demonstrates how to balance a double displacement reaction equation involving calcium phosphate and sulfuric acid. The instructor introduces a trick to simplify the process by treating polyatomic ions as single units. The video guides viewers through counting atoms, applying coefficients, and balancing the equation step-by-step. It also discusses the states of matter for the reactants and products, highlighting that calcium sulfate forms a precipitate. The tutorial emphasizes the importance of efficient balancing techniques, especially for exams.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the video tutorial?

Balancing a single displacement reaction

Learning about acid-base reactions

Balancing a double displacement reaction

Understanding chemical bonding

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which compounds are involved in the reaction discussed in the video?

Magnesium sulfate and nitric acid

Calcium phosphate and sulfuric acid

Sodium chloride and sulfuric acid

Calcium carbonate and hydrochloric acid

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What trick is suggested to simplify balancing double displacement reactions?

Ignoring hydrogen atoms

Counting polyatomic ions as single units

Using a calculator

Balancing metals first

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many phosphate ions are present on the reactant side before balancing?

Four

Three

Two

One

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is placed in front of calcium sulfate to balance the calciums?

One

Three

Two

Four

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many hydrogens are there on the product side after balancing?

Two

Eight

Four

Six

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it beneficial to treat polyatomic ions as single units when balancing equations?

It reduces the number of steps needed

It increases the number of calculations

It helps in identifying the products

It makes the equation more complex

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