Balancing Chemical Reactions and Ions

This video tutorial demonstrates how to balance the chemical equation for lead metal reacting with phosphoric acid (Pb + H3PO4). The instructor uses a trick to simplify the process by treating the phosphate ion as a single unit. The video covers counting atoms on both sides of the equation, balancing phosphate ions, and then balancing hydrogen and lead atoms. The tutorial concludes with tips for handling polyatomic ions in single and double displacement reactions, emphasizing efficiency during exams.

What is the main purpose of the trick mentioned in the video?

• To change the chemical reaction

• To simplify the balancing process

• To increase the number of atoms

• To make the equation more complex

How many lead atoms are present on the reactant side of the equation?

• Four

• One

• Two

• Three

What is the significance of the phosphate ion in the reaction?

• It breaks down into simpler ions

• It is not involved in the reaction

• It is counted as a single unit

• It changes form during the reaction

What coefficient is used to balance the phosphate ions?

• 3

• 2

• 4

• 1

How many hydrogen atoms are present after balancing?

• Four

• Six

• Two

• Eight

What is the final coefficient for lead in the balanced equation?

• 4

• 1

• 2

• 3

What type of reaction is demonstrated in the video?

• Synthesis reaction

• Decomposition reaction

• Single displacement reaction

• Double displacement reaction

How should polyatomic ions be treated in single and double displacement reactions?

• As separate elements

• As a single unit

• They should be ignored

• They should be split into individual atoms

Why is it important to use the trick mentioned in the video during exams?

• It makes the process slower

• It ensures accuracy

• It confuses the examiner

• It speeds up the process

What is the final balanced equation for the reaction?

• Pb + H3PO4 → Pb3(PO4)2 + H2

• 3Pb + 2H3PO4 → Pb3(PO4)2 + 3H2

• Pb + 2H3PO4 → Pb3(PO4)2 + 3H2

• 3Pb + H3PO4 → Pb3(PO4)2 + 3H2