Oxidation Numbers in NaIO4

This video tutorial explains how to determine the oxidation numbers for each element in NaIO4. It begins by noting that NaIO4 is a neutral compound, meaning the oxidation numbers must sum to zero. Sodium, being in Group 1, has a +1 oxidation number. Oxygen typically has a -2 oxidation number. The video then focuses on calculating the oxidation number of iodine, which is bonded to oxygen. By setting up an equation, the video demonstrates that iodine has a +7 oxidation number in NaIO4. The tutorial concludes by summarizing the oxidation numbers of each element in the compound.

What is the overall charge of the compound NaIO4?

• Positive

• Neutral

• Depends on the elements

• Negative

What is the oxidation number of sodium in NaIO4?

• +1

• +2

• -1

• 0

Why is the oxidation number of iodine in NaIO4 not immediately known?

• Because iodine is bonded to oxygen

• Because iodine is in Group 1

• Because iodine is a noble gas

• Because iodine is a metal

What is the oxidation number of oxygen typically, with few exceptions?

• -1

• 0

• -2

• +2

How do you set up the equation to find the oxidation number of iodine in NaIO4?

• 1 + X + 4(-2) = 0

• 1 + X + 4(+1) = 0

• 1 + X + 4(+2) = 0

• 1 + X + 4(-1) = 0

What is the oxidation number of iodine in NaIO4 after solving the equation?

• +5

• +8

• +6

• +7

What should the sum of the oxidation numbers in NaIO4 equal?

• -1

• +2

• 0

• +1