Search Header Logo
Lewis Structures and Formal Charges

Lewis Structures and Formal Charges

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to draw the Lewis structure for iodic acid (HI03). It begins by identifying the molecule as an acid due to the presence of hydrogen. The iodine atom is placed at the center, with oxygen atoms surrounding it, and hydrogen is placed on the outside of one oxygen. The tutorial details the use of 26 valence electrons to form chemical bonds and complete octets. It then calculates formal charges for each atom, finding that adjustments are needed to achieve charges closer to zero. By forming double bonds, the structure is optimized, resulting in zero formal charges for all atoms. The video concludes with a note on iodine's ability to have an expanded octet.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the central atom in the Lewis structure of HIO3?

Carbon

Iodine

Oxygen

Hydrogen

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is hydrogen placed on the outside of an oxygen in the Lewis structure of HIO3?

Because it is more electronegative

Because it is an acid

Because it forms a double bond

Because it has more valence electrons

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to form chemical bonds in HIO3?

8

10

24

26

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on iodine in the initial Lewis structure of HIO3?

-1

0

+2

+1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which oxygen atom has a formal charge of zero in the initial structure?

All oxygen atoms

Oxygen on the left

Oxygen bonded to hydrogen

Oxygen on the right

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What adjustment is made to achieve formal charges of zero on all atoms?

Changing the central atom

Adding more electrons

Forming double bonds

Removing electrons

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it acceptable for iodine to have more than an octet in the final structure?

Because it is highly reactive

Because it is below period 2 on the periodic table

Because it is a noble gas

Because it is in period 1

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?