Boron Atom and Lewis Structures

Boron Atom and Lewis Structures

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains the B2 Lewis structure, focusing on boron's valence electrons and how they form chemical bonds. Initially, electrons are placed between two boron atoms to form a single bond. However, to achieve stability, electrons are moved to form double and then triple bonds. Despite this, boron does not achieve an octet, as it is an exception to the octet rule, requiring only six valence electrons. The tutorial concludes with a correct representation of the B2 Lewis structure, highlighting boron's unique electron configuration.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does a single boron atom have?

Six

Three

Four

Two

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons available for the B2 Lewis structure?

Ten

Six

Eight

Four

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of bond is initially formed between the two boron atoms?

No bond

Double bond

Single bond

Triple bond

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why does boron not follow the octet rule?

It has too many electrons

It only needs six valence electrons

It forms a quadruple bond

It is a metal

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final type of bond formed between the two boron atoms in the B2 Lewis structure?

Quadruple bond

Triple bond

Double bond

Single bond

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many pairs of electrons are shared in the final B2 Lewis structure?

Four pairs

Three pairs

Two pairs

One pair

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the B2 Lewis structure in terms of the octet rule?

It follows the octet rule perfectly

It shows an exception to the octet rule

It has more than eight electrons

It is irrelevant to the octet rule