Bromine and Fluorine Bonding Concepts

Bromine and Fluorine Bonding Concepts

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to draw the Lewis structure for BrF2. Bromine and Fluorine's valence electrons are calculated, resulting in an odd number, indicating an unpaired electron. Bromine is placed in the center with Fluorines on either side, forming bonds and completing octets. Bromine, being in period 3, can hold more than eight electrons, allowing for the placement of the remaining electron. The formal charges are checked, confirming the structure's validity.

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6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does Bromine contribute in the BrF2 molecule?

6

7

5

8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons in BrF2?

18

19

20

21

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is one electron unpaired in the Lewis structure of BrF2?

Due to the high electronegativity of Bromine

Because of an odd number of valence electrons

Due to the presence of a lone pair on Fluorine

Because of an even number of valence electrons

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons are used to form chemical bonds between Bromine and Fluorine in BrF2?

4

2

6

8

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of Bromine being in period 3 of the periodic table?

It forms ionic bonds with Fluorine

It has a higher electronegativity than Fluorine

It can hold more than 8 valence electrons

It can only hold 8 valence electrons

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on each atom in the BrF2 molecule?

+2

0

-1

+1