Volume and Rate of Change

Volume and Rate of Change

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to solve a problem involving a spherical balloon being filled with helium at a given rate. It covers understanding derivatives, setting up and solving an integration to find the volume of helium, and evaluating the constant of integration using initial conditions. The final calculation determines the volume of helium when time equals six minutes.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the rate of change of volume with respect to time for the spherical balloon?

dv/dt = 2πr^2

dv/dt = πr^2

dv/dt = 4πr^2

dv/dt = 4πr

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the equation r = 1/4 t represent in the context of the problem?

The final volume of the balloon

The initial volume of the balloon

The relationship between radius and time

The rate of change of volume

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it necessary to substitute r with t in the integration process?

To find the initial volume

To simplify the equation

To express the equation in terms of time

To eliminate the constant of integration

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical process is used to find the volume from the rate of change?

Differentiation

Substitution

Integration

Simplification

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of determining the constant of integration in this problem?

To express the volume in terms of radius

To calculate the rate of change of volume

To ensure the integration is accurate

To find the initial volume of the balloon

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final expression for the volume of the balloon after integration?

v = πt^3/4

v = πt^2/12

v = πt^3/12

v = 2πt^3/12

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the statement 'assume the balloon was initially deflated'?

It indicates the balloon's final state

It helps in calculating the rate of change

It provides the initial condition for volume

It simplifies the integration process

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