Rectangle Optimization and Properties

Rectangle Optimization and Properties

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explores using calculus to find stationary points, focusing on turning points that are either maximum or minimum. It applies this concept to a practical problem of minimizing the perimeter of a rectangle with a constant area. The tutorial outlines four steps: modeling the situation, identifying restrictions, using calculus, and answering the question. It emphasizes the importance of considering restrictions and endpoints when applying calculus to real-world problems.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the two categories of turning points discussed in the video?

Linear and non-linear

Concave up and concave down

Positive and negative

Increasing and decreasing

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the rectangle problem, what is the constant area given?

60 square centimeters

24 square centimeters

36 square centimeters

48 square centimeters

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in the four-step optimization process?

Use calculus

Answer the question

Look for restrictions

Create a model

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the width of the rectangle determined in the model?

By subtracting the length from the area

By adding the length to the area

By multiplying the length by 2

By dividing the area by the length

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for the perimeter of the rectangle in terms of x?

2x + 36

2x + 72/x

x + 36/x

x + 72

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't x be equal to zero in the rectangle problem?

Because it would make the area undefined

Because it would make the width zero

Because it would make the length negative

Because it would make the perimeter zero

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the perimeter function with respect to x?

2 + 72/x^2

2 - 72x^2

2 + 72x^2

2 - 72/x^2

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