Proof by Contradiction in Mathematics

Proof by Contradiction in Mathematics

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains the proof by contradiction method, a key mathematical technique. It begins with an overview of the method, followed by detailed steps. An example is provided to illustrate the concept: proving that no integer is both even and odd. The video analyzes the logical form of the statement, applies definitions, and performs manipulations to reach a contradiction, thereby proving the original statement. The tutorial concludes with a summary of the proof process.

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8 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary purpose of proof by contradiction in mathematics?

To use empirical evidence to support a mathematical claim.

To simplify complex mathematical expressions.

To assume the negation of a statement and derive a contradiction.

To directly prove a statement by checking all possibilities.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In proof by contradiction, what is the first step when trying to prove a claim P?

Assume not P is true.

Assume not P is false.

Assume P is true.

Assume P is false.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the goal when manipulating assumptions in proof by contradiction?

To reach a logical conclusion.

To simplify the statement.

To arrive at a nonsensical statement.

To find a supporting example.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it challenging to prove directly that no integer is both even and odd?

Because integers can change properties.

Because it requires checking every integer.

Because even and odd are not well-defined.

Because integers are infinite.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the statement 'No integer is both even and odd' rewritten for proof by contradiction?

As a specific example of an integer.

As a claim about a single integer.

As a universal statement about all integers.

As a conditional statement.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does assuming the negation of the theorem imply in this proof?

That no integers are even.

That all integers are both even and odd.

That there exists at least one integer that is both even and odd.

That no integers are odd.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the contradiction reached in the proof regarding K1 and K2?

K1 and K2 are both even.

K1 and K2 are both odd.

K1 plus K2 is zero.

K1 minus K2 is both an integer and a fraction.

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the conclusion of the proof by contradiction demonstrate?

That the theorem cannot be proven.

That the original assumption was correct.

That the original theorem is false.

That the original assumption leads to a contradiction, proving the theorem true.