Limits and Continuity Concepts

Limits and Continuity Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to determine the continuity of a function at a specific point, using the example of a function defined at X=0. It involves splitting the function into three regions: X less than 0, X equal to 0, and X greater than 0. The tutorial demonstrates how to calculate the left-hand limit, the value of the function at X=0, and the right-hand limit. If these values are equal, the function is continuous at that point. The video concludes with a call to action for viewers to like and subscribe.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus when determining the continuity of a function at a specific point?

Checking the derivative at that point

Checking the function's value at that point

Checking the integral of the function at that point

Checking the limits from both sides and the function's value at that point

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the function split to check its continuity at x = 0?

Into a single region: x = 0

Into four regions: x < 0, x = 0, x > 0, and x = 1

Into three regions: x < 0, x = 0, and x > 0

Into two regions: x < 0 and x > 0

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which function is used to calculate the left-hand limit for x < 0?

f(x) = sin(x)/x

f(x) = cos(x)

f(x) = x + 1

f(x) = x^2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the left-hand limit as x approaches 0 for f(x) = sin(x)/x?

1

0

Infinity

-1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function value at x = 0?

2

Undefined

1

0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which function is used to calculate the right-hand limit for x > 0?

f(x) = cos(x)

f(x) = x + 1

f(x) = sin(x)/x

f(x) = x^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the right-hand limit as x approaches 0 for f(x) = x + 1?

0

1

2

-1

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