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Quadratic Equations and Pythagorean Theorem

Quadratic Equations and Pythagorean Theorem

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to solve a quadratic equation problem involving two cars leaving an intersection at the same time, one heading north and the other west. The problem is set up using the Pythagorean theorem, and the quadratic equation is solved using algebraic methods, including the quadratic formula. The final solution determines the distances traveled by each car.

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16 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical concept is primarily used in this video?

Calculus

Linear equations

Quadratic equations

Trigonometry

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the problem, how do the two cars initially move?

Both go west

One goes north, the other goes west

Both go north

One goes east, the other goes south

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What geometric shape is formed by the paths of the cars?

Rectangle

Right triangle

Square

Circle

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the length of the hypotenuse in the right triangle formed by the cars' paths?

200 miles

150 miles

100 miles

50 miles

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the car heading west travels 20 miles farther than the car going north, how is the distance of the car going north represented?

x + 20

x - 20

x

20

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation is set up using the Pythagorean theorem?

x^2 + (x + 20)^2 = 50^2

x^2 + (x + 20)^2 = 100^2

x^2 - (x + 20)^2 = 100^2

x^2 + (x - 20)^2 = 100^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplified form of the quadratic equation before solving?

2x^2 + 20x - 4800 = 0

x^2 + 40x + 400 = 0

2x^2 + 40x - 9600 = 0

x^2 + 20x - 4800 = 0

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