Object Motion and Quadratic Functions

Object Motion and Quadratic Functions

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to determine the maximum height and the time it takes for an object shot straight up to hit the ground using a quadratic formula. The instructor demonstrates finding the vertex to calculate the maximum height and uses both intuitive and algebraic methods to find the time for the object to return to the ground.

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13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary objective of the problem discussed in the video?

To determine the maximum height and time to hit the ground.

To measure the distance traveled horizontally.

To find the speed of the object.

To calculate the weight of the object.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the variable 'T' represent in the quadratic formula?

Time in seconds

Time in minutes

Height in meters

Height in feet

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to find the vertex of the quadratic equation?

Negative B over 2A

Negative A over 2B

B minus A

A plus B

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the time at which the maximum height is reached?

8 seconds

16 seconds

24 seconds

32 seconds

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the maximum height calculated once the time is known?

By adding the time to the initial height

By substituting the time into the quadratic formula

By dividing the time by the acceleration

By multiplying the time by the initial velocity

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the maximum height reached by the object?

2048 feet

5120 feet

3072 feet

4096 feet

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the intuitive method to find the time it takes for the object to hit the ground?

Double the time it takes to reach maximum height

Subtract the time to reach maximum height from 100

Multiply the time to reach maximum height by 3

Divide the time to reach maximum height by 2

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