Differential Equations in Mixing Problems

Differential Equations in Mixing Problems

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

This video tutorial explains how to solve mixing problems using first-order separable differential equations. It begins with an introduction to mixing problems, followed by setting up a specific problem involving a tank with brine. The tutorial then derives and solves the differential equation, applies initial conditions, and concludes with the final solution. The video emphasizes understanding the rate of change as the difference between the rate in and rate out, and provides a step-by-step guide to solving these types of problems.

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9 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary mathematical tool used to solve mixing problems in this video?

Linear algebra

First order separable differential equations

Integral calculus

Probability theory

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the problem setup, what is the initial amount of dissolved salt in the tank?

20 kilograms

5 kilograms

15 kilograms

10 kilograms

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the rate at which pure water enters the tank?

15 liters per minute

20 liters per minute

5 liters per minute

10 liters per minute

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the change in the amount of salt in the tank determined?

By the initial concentration of salt

By the rate in minus the rate out of salt

By the rate of water flow

By the volume of the tank

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the concentration of salt in the incoming water?

15%

10%

5%

0%

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the form of the separable differential equation derived in the video?

a' = a + b

a' = -a/100

a' = a/100

a' = -a/10

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition used to solve the differential equation?

a(0) = 10

a(0) = 20

a(0) = 15

a(0) = 5

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