Calculus: Area Between Curves

Calculus: Area Between Curves

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Jennifer Brown

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the area between curves when functions intersect multiple times?

Use a graphing calculator to plot the functions

Integrate each function separately

Calculate the derivative of each function

Set the functions equal to each other to find intersection points

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When setting up integrals for areas between curves, why might you need multiple integrals?

To simplify the calculation process

To avoid using a calculator

To account for different functions being on top in different regions

To ensure all intersections are included

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to set up boundaries for integrals when calculating areas between curves?

To determine the limits of integration

To avoid using a calculator

To simplify the functions

To ensure the functions are continuous

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of using absolute values in integrals when calculating areas between curves?

To make the calculation faster

To ensure all areas are positive

To avoid using a calculator

To simplify the integral setup

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens if you do not use absolute values in integrals for areas between curves?

The area calculation becomes faster

The area might be negative

The functions cannot be integrated

The integral becomes undefined

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the advanced example, how many integrals are needed to cover all regions?

One

Two

Three

Four

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the advanced example, what is the significance of the square root of 2 in the integrals?

It is used to calculate the derivative

It is the maximum value of the function

It represents a point of intersection

It simplifies the integral

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