Volume of Irregular Pyramids

What is the formula for the volume of a pyramid with an irregular polygon base?

• V = Bh

• V = (1/3)Bh

• V = (1/2)Bh

• V = (1/3)πr²h

What is the formula for calculating the area of a trapezoid?

• A = l * w

• A = (b1 + b2) * h

• A = ((b1 + b2)/2) * h

• A = 1/2 * b * h

A trapezoidal base has parallel sides of 4 inches and 7 inches, and a height of 3 inches. What is its area?

• 10.5 in²

• 16.5 in²

• 21 in²

• 33 in²

A pyramid has a trapezoidal base with an area of 16.5 in² and a height of 15 inches. What is the volume of the pyramid?

• 82.5 in³

• 165 in³

• 247.5 in³

• 495 in³

What is the general formula for calculating the volume of a pyramid?

• V = Bh

• V = (1/2)Bh

• V = (1/3)Bh

• V = (1/4)Bh

What is the area of the rectangular part of the pentagonal base?

• 48 cm²

• 72 cm²

• 96 cm²

• 120 cm²

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What is the area of the triangular part of the pentagonal base?

• 8 cm²

• 12 cm²

• 16 cm²

• 24 cm²

What is the total volume of the irregular pentagonal pyramid?

• 480 cm³

• 560 cm³

• 640 cm³

• 720 cm³

A pyramid has a right triangular base. If the legs of the base measure 15 inches and 17 inches, what are these measurements considered for the triangle's area calculation?

• Base and height

• Hypotenuse and leg

• Side and perimeter

• Radius and diameter