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BC Integration

Total questions: 19

Worksheet time: 55mins

Name
Class
Date
1.
For u-substitution, what should be used for u here:
∫ (tan4xsec2x)dx
a)
tanx
b)
tan4x
c)
no u needed
d)
tanxsecx
2.
For u-substitution what should bethe u here?
∫(5xsin(2x2))dx
a)
2x2
b)
4x
c)
5x
d)
no u substitution needed
3.
For u-substitution what should be "du" in this integral?
a)
tanxsecx dx
b)
secx dx
c)
sec2x dx
d)
tanx dx
4.
What method would you use here?
a)
antiderivatives
b)
u-substitution
c)
integration by parts
d)
slope fields
5.
What method would you use here?
a)
antiderivatives
b)
u-substitution
c)
integration by parts
d)
slope fields
6.
What method would you use here?
a)
antiderivatives
b)
u-substitution
c)
integration by parts
d)
slope fields
7.
What method would you use here?
a)
antiderivatives
b)
u-substitution
c)
integration by parts
d)
slope fields
8.
What method would you use here?
a)
antiderivatives
b)
u-substitution
c)
integration by parts
d)
slope fields
9.
What method would you use here?
a)
antiderivatives
b)
u-substitution
c)
integration by parts
d)
slope fields
10.
What would you choose for your u here if you used integration by parts?
a)
x
b)
sinx
c)
cosx
d)
ex
11.
What would you choose for your u here if you used integration by parts?
a)
t
b)
3t
c)
e2t
d)
et
12.
What would you choose for your u here if you used integration by parts?
a)
x
b)
x4
c)
e-x
d)
ex
13.
What is ILATE
a)
a poor excuse
b)
sequence for differentiation
c)
a yummy beverage
d)
inverse trig, logs, algebra, trig, exponential (finding u and dv)
14.
How many times would you need integration by parts here
a)
0 (trick question)
b)
1
c)
2
d)
∞ 
15.
How many times would you need integration by parts here
a)
0 (trick question)
b)
1
c)
2
d)
16.
No calculator
a)
A
b)
B
c)
C
d)
E
17.
How many times would you need integration by parts here
a)
0 (trick question)
b)
1
c)
2
d)
∞ 
18.
Solve via integration by parts
a)
xcosx-sinx + C
b)
x(-cosx)-sinx + C
c)
x(-cosx)+sinx + C 
d)
x(cosx)+sinx + C 
19.
Solve via integration by parts
a)
3t(e2t)/2 - (e2t)/4 + C
b)
3t(e2t)⋅2 - 3(e2t)⋅4 + C 
c)
3(e2t) - (e2t)/4 + C
d)
3t(e2t)/2 - 3(e2t)/4 + C