NEW
Font size
WorksheetsDataphobia-Are You Smarter Than Your Friend?
Total questions: 50
Worksheet time: 4hrs 31mins
The formula definition of the mass moment of inertia about an axis is ___________ .
∫ r dm
∫ r2 dm
∫ m dr
∫ m2 dr
The parallel-axis theorem can be applied to ________ .
Only the Moment of inertia
Only the mass moment of inertia
Both on Moment of inertia and Mass moment of inertia
None of the above
A particle of mass 2 kg is located 1 m down the y-axis. What are the Mass moment of inertia (MMI) of the particle about the x, y, and z axes, respectively?
(2, 0, 2)
(0, 2, 2)
(0, 2, 2)
(2, 2, 0)
Consider a rectangular frame made of four slender bars and four axes (zP, zQ, zR and zS) perpendicular to the screen and passing through points P, Q, R, and S, respectively. About which of the four axes will the MMI of the frame be the lowest?
zP
zS
zQ
zR
If you know only λA, you can determine the __________ of A uniquely.
magnitude
angles (α,β, and γ)
components (Ax, AY and Az)
all of the above
For a force vector, the following parameters are randomly generated. The magnitude is 0.9, α = 30º, β=70º and γ = 100º. What is wrong with this 3D vector?
Magnitude is too small
Angles are too large
All three angles are arbitrarily picked
All three angles are between 0º to 180º
A position vector, rPQ is obtained by
coordinate of Q minus coordinate of P
Corrdinate of P minus coordinate of Q
Coordinate of Q minus coordinate of the origin
Coordinate of the origin minus coordinate of P
If F and r are force vector and position vectors, respectively, in SI units, what are the units of the expression (r*(F/F))?
Newton
dimensionless
Meter
Newton-meter
The vector operation (P × Q) ⋅ R equals
P × (Q ⋅ R)
R ⋅ (P × Q)
(P ⋅ R) × (Q ⋅ R)
(P × R) ⋅ (Q × R)
In statics, a couple is defined is defined as ___________ separated by a perpendicular distance.
two forces in the same direction
two forces of equal magnitude
two forces of equal magnitude acting in the same direction
two forces of equal magnitude acting in opposite directions
If three couples act on a body, the overall result is that
the net force is not equal to 0
the net force and net moment are equal to 0
the net moment equals 0 but the net force is not necessarily equals to 0
the net force equals 0 but the net moment is not necessarily equal to 0
The original force and couple system and an equivalent force -couple system have the same _________ effect on a body.
internal
external
internal and external
microscopic
Consider two couples acting on a body. The simplest possible equivalent system at any arbitrary point on the body will have
one force and one couple moment
one force
one couple moment
two couple moments
Consider three couples acting on a body. Equivalent systems will be ___________ at different points on the body.
different when located
the same even when located
zero when located
none of the above
Internal forces are not shown on a free-body diagram because the internal forces are _____. (Choose the most appropriate answer.)
Equal to zero
Equal and opposite and they do not affect the calculations
Negligibly small
Not important
How many unknown support reactions are there in this problem?
Two forces and two couple moments
One force and two couple moments
Three forces
Three forces and one couple moment
A rigid body is subjected to forces as shown. This body can be considered as a ______ member.
Single-force
Two-force
Three-force
Six-force
A beam is supported by a pin joint and a roller. How many support reactions are there and is the structure stable for all types of loadings?
(3, Yes)
(4, Yes)
(3, No)
(4, No)
If a support prevents rotation of a body about an axis, then the support exerts a ________ on the body about that axis.
Couple moment
Both A and B.
Force
None of the above.
Five forces
Six forces
Four forces and two moments
Four forces and one moment
If an additional couple moment in the vertical direction is applied to rod AB at point C, then what will happen to the rod?
The rod remains in equilibrium as the cables provide the necessary support reactions.
The rod remains in equilibrium as the ball-and-socket joint will provide the necessary resistive reactions.
The rod becomes unstable as the cables cannot support compressive forces
The rod becomes unstable since a moment about AB cannot be restricted
Moment of inertia of any section about an axis passing through its center of gravity is
maximum
minimum
depends upon the dimensions of the section
depends upon the shape of the section
The moment of inertia of a triangular section of base ‘b’ and height ‘h’ about an axis passing through its base is __________ times the moment of inertia about an axis passing through its center of gravity and parallel to the base
9
4
2
3
The moment of inertia of a circular section about an axis perpendicular to the section is
πd3/32
πd4/64
πd4/32
πd3/64
The moment of inertia of a circular section of base ‘b’ and height ‘h’ about an axis passing through its vertex and parallel to base is
bh3/12
bh3/36
bh3/3
bh3/4
Determine the approximate amount of paint needed to cover the surface of the water storage tank. Assume that a liter of paint covers 2.5 m2. Also, what is the total inside volume of the tank.
27.6 liters of paint, V = 52.6 m3
20.1 liters of paint, V = 50.3 m3
26.4 liters of paint, V = 56.5 m3
25.1 liters of paint, V = 55.0 m3
Determine the distance to the centroid axis of the beam's cross-sectional area. Neglect the size of the corner welds at A and B for the calculation.
ý = 75.2 mm
ý = 97.5 mm
ý = 85.9 mm
ý = 102.5 mm
Locate the centroid of the shaded area.
x̄ = 0.667 m, ȳ= 2.40 m
x̄ = 0.5 m, ȳ= 2.80 m
x̄ = 0.8 m, ȳ= 2.00 m
x̄ = 0.60 m, ȳ= 2.60 m
Determine the volume of concrete needed to construct the circular curb.
V = 1.083 m3
V = 1.309 m3
V = 1.756 m3
V = 8.67 m3
Determine the distance ȳ to the centroidal axis x̄x̄ of the beam's cross-sectional area.
ȳ = 112.3 mm
ȳ = 125mm
ȳ = 100 mm
ȳ = 91.7 mm
Determine the magnitude of the resultant force by adding the rectangular components of the three forces.
R = 29.7 N
R = 54.2 N
R = 90.8 N
R = 24.0 N
Express the force F2 in Cartesian vector form.
F2 = (155 i + 155 j + 300 k) lb
F2 = (212 i + 212 j - 519 k) lb
F2 = (155 i + 155 j - 300 k) lb
F2 = (367 i + 367 j - 300 k) lb
Determine the projection of the position vector r along the aa axis.
raa = 35.3 m
raa = 6.28 m
raa = 5.42 m
raa = 5.61 m
What is the projection of the force F2 along the positive axis?
F2y = 170.0 N
F2y = —80.0 N
F2y = 90.0 N
F2y = 120.0 N
The gusset plate G of a bridge joint is subjected to the two member forces at A and B. If the force at B is horizontal and the force at A is directed at = 30°, determine the magnitude and direction of the resultant force.
R = 458 N, θ = 97.5° CCW
R = 252 N, θ = 82.5° CCW
R = 252 N, θ = 97.5° CCW
R = 458 N, θ = 82.5° CCW
Two forces act on a block. Determine the angle θ between them.
θ = 135º
θ = 65.1º
θ = 45º
θ = 114.9º
Cable BC exerts a force of F = 28 N on the top of the flagpole. Determine the projection of this force along the positive z axis of the pole.
F = 24 N
F = -24 N
F = 12 N
F = -12 N
Determine the magnitudes of the resultant force and its direction measured from the positive x axis.
R = 10.80 kN, θ = 68.2° CW
R = 14.00 kN, θ = 60.0° CW
R = 13.6 kN, θ = 21.5° CW
R = 12.49 kN, θ = 43.9° CW
If solving the question in 3D calculations is difficult, then use the 2D system and then equate the ratio of the product of the centroid of the section to its mass to the total mass of the body to the centroid.
True
False
The use of centroid comes in picture as if the non-Uniform loading is of the type of parabola then what will be the best suited answer among the following?
The net force will act the centre of the parabola
The net load will not be formed as all the forces will be cancelled
The net force will act at the centroid of the parabola
The net force will act on the base of the loading horizontally
Centroid of a body does depends upon the small weights of tiny particles. Which statement is right for force acting by the small particles of the body having it’s vector form as = Ai + Bj + Ck?
In rectangular components representation of any vector we have vector F = Fi + Fj + Fk
In rectangular components representation of any vector we have vector F = Fx + Fy + Fz
In rectangular components representation of any vector we have vector F = Ax + By + Cz
In rectangular components representation of any vector we have vector F = Ai + Bj + Ck
Centroid determination involves the calculations of various forces. In that forces are having various properties. That is force is developed by a support that not allows the ________ of its attached member.
Translation
Rotation
Subtraction
Addition
The supports in the 3D are having more than three reaction forces. Because they are having three axis on which the components of the forces need to be zero.
The first part of the statement is false and other part is true.
The first part of the statement is false and other part is false too
The first part of the statement is true and other part is false
The first part of the statement is true and other part is true too
Two of the things of the composite materials are to be known so that their properties can be varied. Which of the following is one of them?
Weight of the centre of gravity
Weight of the centre of body
Location of the centre of gravity
Location of the centre of mass
The centre of mass for the composite body is the ratio of ________ to _________
The product of centroid and mass to the total weight
The addition of centroid and weight to the total weight
The subtraction of centroid and weight to the total weight
The product of centroid and mass to the total mass
The total of all the masses of small particles adds up to give the total body mass of the composite body. This mass lies along with gravity gives a force vector which is being passed by ________
Axis of rotation
Axis of rolling
Centre of Gravity
Centre of mass
The all small masses that are being applied by all the infinite particles of the body act __________ to each other.
Parallel
Perpendicular
Divergent
Collinear
The magnitude of the resultant of the two vectors in calculations for cable subjected to its own weight is always:
Greater than one of the vector’s magnitude
Smaller than one of the vector’s magnitude
Depends on the angle between them
Axis we choose to calculate the magnitude
The tensile force acting on the cable subjected to its own weight is in which direction with respect to the cable?
At an angle of 2 radians
Tangential
Parallel
Perpendicular
For calculations involved for cable subjected to its own weight all the vectors quantities obey :
Parallelogram law of addition
Parallelogram law of multiplication
Parallelogram law of addition of square root of their magnitudes
Parallelogram law of addition of square of their magnitudes
