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WorksheetsBasic Trig Identities
Total questions: 20
Worksheet time: 2hrs 40mins
Please select the correct solution
cos2x + sin 2x =
1
csc 2 x + sec 2 x
sin 2 x
1 - sin 2 x
Solve the following for tan2θ
1 + tan2θ= sec2θ
tan2θ = sec2θ + 1
tan2θ = sec2θ - 1
tanθ = secθ - 1
tan2θ = opp/adj
Rewrite tan(x) in terms of sin(x) and cos(x).
tan(x) = cos(x)/sin(x)
tan(x) = 1/cot(x)
tan(x) = sin(x)/cos(x)
tan(x) = opp/adj
Simplify:
tan x cotx −cos2x
tanx
cotx
sin2x
cos2x
tan(x)csc(x)
Is this a pythagorean identity?
tan2x + 1 = secx
Yes
No
Simplify.
tan2x
sinx
cot2x
cosx
Simplify
cos x(tan x + cot x)
sinx
cscx
Tanx+1
None of the above
cot θ=
cosθ/sinθ
sinθ/cosθ
tanθ
1/cosθ
Simplify
sinx (cscx +cotx)
cos x + 1
csc x +1
cos x - 2
secx
Simplify
(secx)(cotx)(sinx)
sin x
- sin x
1
-1
Solve the following for cot2θ:
1 + cot2θ = csc2θ
1 = cot2θ + csc2θ
cot2θ =1 - csc2θ
cot2θ = csc2θ -1
cot2θ = adj/opp
cotxcscx
tanx
sin x
cos x
sec x
secxtanx
cosx
cscx
cotx
sinx
(cscx)(tanx)
sinx
cotx
cosx
secx
(cosx)(sinx)(cscx)(secx)
tanx
cotx
1
−1
csc(λ)
sec(90°−λ)
sin(90°−λ)
cot(90°−λ)
1
tan(β)
sec(2π−β)
sin(2π−β)
cot(2π−β)
1
What is Ms Cornwell's name going to be?
Cornwell
Campbell
Wright
Johnson
When is the test for Unit 4?
Dec 12
Apr 31
Feb 30
Sep 31
