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CHOOSE the Kinematic EQ of Motion

Total questions: 40

Worksheet time: 13mins

Name
Class
Date
1.

Given:  
 vi=10ms    …    vf=15ms   …    a=10 ms2v_i=10\frac{m}{s}\ \ \ \ \ldots\ \ \ \ v_f=15\frac{m}{s}\ \ \ \ldots\ \ \ \ a=10\ \frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

2.

Given:  
 vi=0ms  …   t=8.5 s  …  a=1.6ms2v_i=0\frac{m}{s}\ \ \ldots\ \ \ t=8.5\ s\ \ \ldots\ \ a=1.6\frac{m}{s^2}  
Which equation would you choose to solve for Final Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

3.

Given:
 vi=0ms   …    vf=−15ms  ⋯   a=−9.8ms2v_i=0\frac{m}{s}\ \ \ \ldots\ \ \ \ v_f=-15\frac{m}{s}\ \ \cdots\ \ \ a=-9.8\frac{m}{s^2} 
Which equation would you choose to solve for displacement (distance)?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Can't be done in a single step

4.

Given:
 vi=0ms    …    vf=25ms    …    d=250 mv_i=0\frac{m}{s}\ \ \ \ \ldots\ \ \ \ v_f=25\frac{m}{s}\ \ \ \ \ldots\ \ \ \ d=250\ m 
Which equation would you choose to solve for acceleration?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Cannot be done in a single step

5.

Given:
 d=−25m   …   vi=0ms   …    a=−9.8ms2d=-25m\ \ \ \ldots\ \ \ v_i=0\frac{m}{s}\ \ \ \ldots\ \ \ \ a=-9.8\frac{m}{s^2} 
Which equation would you choose to solve for time?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Cannot be done in a single step

6.

Given:
 d=−25m   …  vi=0ms   …  vf=12msd=-25m\ \ \ \ldots\ \ v_i=0\frac{m}{s}\ \ \ \ldots\ \ v_f=12\frac{m}{s} 
Which equation would you choose to solve for time?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Cannot be done in a single step

7.

Given:  
 vi=10ms   …  d=20m   …   a=5ms2v_i=10\frac{m}{s}\ \ \ \ldots\ \ d=20m\ \ \ \ldots\ \ \ a=5\frac{m}{s^2}  
Which equation would you choose to solve for Final Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

8.

Given:  
 vf=10ms  …   d=50m   …   a=0.5ms2v_f=10\frac{m}{s}\ \ \ldots\ \ \ d=50m\ \ \ \ldots\ \ \ a=0.5\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

9.

Given:  
 vf=5ms  …   t=10s  …  a=0.8ms2v_f=5\frac{m}{s}\ \ \ldots\ \ \ t=10s\ \ \ldots\ \ a=0.8\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

10.

Given:  
 d=24m  …  t=8s   …   a=0.8ms2d=24m\ \ \ldots\ \ t=8s\ \ \ \ldots\ \ \ a=0.8\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

11.

Given:  
 d=24m   …  t=8s  …  a=0.8ms2d=24m\ \ \ \ldots\ \ t=8s\ \ \ldots\ \ a=0.8\frac{m}{s^2}  
Which equation would you choose to solve for Final Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

12.

Given:  
 d=75m  … vi=0ms  …  a=11.5ms2d=75m\ \ \ldots\ v_i=0\frac{m}{s}\ \ \ldots\ \ a=11.5\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

13.

Given:  
 d=98m  …  vi=5ms    …   vf=22msd=98m\ \ \ldots\ \ v_i=5\frac{m}{s}\ \ \ \ \ldots\ \ \ v_f=22\frac{m}{s}  
Which equation would you choose to solve for acceleration?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

14.

Given:  
 d=62m   …   vi=20ms  …   vf=12msd=62m\ \ \ \ldots\ \ \ v_i=20\frac{m}{s}\ \ \ldots\ \ \ v_f=12\frac{m}{s}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

15.

Given:  
 vf=6ms   …  d=18m   …   a=−5ms2v_f=6\frac{m}{s}\ \ \ \ldots\ \ d=18m\ \ \ \ldots\ \ \ a=-5\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

16.

Given:  
 vf=90ms   …  d=2005m  …  a=−6.5ms2v_f=90\frac{m}{s}\ \ \ \ldots\ \ d=2005m\ \ \ldots\ \ a=-6.5\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

17.

Given:  
 vi=3ms  …   vf=4ms   ⋯  a=0.54ms2v_i=3\frac{m}{s}\ \ \ldots\ \ \ v_f=4\frac{m}{s}\ \ \ \cdots\ \ a=0.54\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

18.

Given:  
 vi=2ms   …  vf=18ms   …  a=1.66ms2v_i=2\frac{m}{s}\ \ \ \ldots\ \ v_f=18\frac{m}{s}\ \ \ \ldots\ \ a=1.66\frac{m}{s^2}  
Which equation would you choose to solve for displacement (distance) ?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

19.

Given:  
 vi=20ms   …  vf=32ms …  t=8sv_i=20\frac{m}{s}\ \ \ \ldots\ \ v_f=32\frac{m}{s}\ \ldots\ \ t=8s  
Which equation would you choose to solve for acceleration?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

20.

Given:  
 vi=0ms   …  d=−20m  …   t=5sv_i=0\frac{m}{s}\ \ \ \ldots\ \ d=-20m\ \ \ldots\ \ \ t=5s  
Which equation would you choose to solve for acceleration?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

21.

Given:  
 vi=20ms  …  vf=4ms   …   a=−2ms2v_i=20\frac{m}{s}\ \ \ldots\ \ v_f=4\frac{m}{s}\ \ \ \ldots\ \ \ a=-2\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

22.

Given:  
 vi=5ms   …   t=15s   …   a=2.5ms2v_i=5\frac{m}{s}\ \ \ \ldots\ \ \ t=15s\ \ \ \ldots\ \ \ a=2.5\frac{m}{s^2}  
Which equation would you choose to solve for Final Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

23.

Given:
 vi=0ms   …  vf=10ms   …  a=25.2ms2v_i=0\frac{m}{s}\ \ \ \ldots\ \ v_f=10\frac{m}{s}\ \ \ \ldots\ \ a=25.2\frac{m}{s^2} 
Which equation would you choose to solve for displacement (distance)?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Can't be done in a single step

24.

Given:
 vi=50ms  …   vf=0ms   …   d=150mv_i=50\frac{m}{s}\ \ \ldots\ \ \ v_f=0\frac{m}{s}\ \ \ \ldots\ \ \ d=150m 
Which equation would you choose to solve for acceleration?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Cannot be done in a single step

25.

Given:
 d=20m   …   vi=2ms   …   a=6ms2d=20m\ \ \ \ldots\ \ \ v_i=2\frac{m}{s}\ \ \ \ldots\ \ \ a=6\frac{m}{s^2} 
Which equation would you choose to solve for time?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Cannot be done in a single step

26.

Given:
 d=40m  …   vi=35ms  …  vf=10msd=40m\ \ \ldots\ \ \ v_i=35\frac{m}{s}\ \ \ldots\ \ v_f=10\frac{m}{s} 
Which equation would you choose to solve for time?

a)

vf=vi+atv_f=v_i+at

b)

d= (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t

c)

d=vit+12at2d=v_it+\frac{1}{2}at^2

d)

vf2=vi2+2adv_f^2=v_i^2+2ad

e)

Cannot be done in a single step

27.

Given:  
 vi=0ms  …  d=50m  …  a=4ms2v_i=0\frac{m}{s}\ \ \ldots\ \ d=50m\ \ \ldots\ \ a=4\frac{m}{s^2}  
Which equation would you choose to solve for Final Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

28.

Given:  
 vf=−20 ms  …  d=−50m   …  a=−2.5ms2v_f=-20\ \frac{m}{s}\ \ \ldots\ \ d=-50m\ \ \ \ldots\ \ a=-2.5\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

29.

Given:  
 vf=−15ms   …   t=12s   …   a=−3.5ms2v_f=-15\frac{m}{s}\ \ \ \ldots\ \ \ t=12s\ \ \ \ldots\ \ \ a=-3.5\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

30.

Given:  
 d=−14 m   …   t=4s   …   a=−4.4ms2d=-14\ m\ \ \ \ldots\ \ \ t=4s\ \ \ \ldots\ \ \ a=-4.4\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

31.

Given:  
 d =−86m   …    t=20s   …   a=−0.6ms2d\ =-86m\ \ \ \ldots\ \ \ \ t=20s\ \ \ \ldots\ \ \ a=-0.6\frac{m}{s^2}  
Which equation would you choose to solve for Final Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

32.

Given:  
 d=−75m   …   vi=20ms   …   a=−1.5ms2d=-75m\ \ \ \ldots\ \ \ v_i=20\frac{m}{s}\ \ \ \ldots\ \ \ a=-1.5\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

33.

Given:  
 d =−98m   …   vi=6ms   …    vf=−15msd\ =-98m\ \ \ \ldots\ \ \ v_i=6\frac{m}{s}\ \ \ \ldots\ \ \ \ v_f=-15\frac{m}{s}  
Which equation would you choose to solve for acceleration?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

34.

Given:  
 d=62m    …   vi=−2ms   …   vf=12msd=62m\ \ \ \ \ldots\ \ \ v_i=-2\frac{m}{s}\ \ \ \ldots\ \ \ v_f=12\frac{m}{s}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

35.

Given:  
 vf=−4ms   …   d =−20m   …   a=1ms2v_f=-4\frac{m}{s}\ \ \ \ldots\ \ \ d\ =-20m\ \ \ \ldots\ \ \ a=1\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

36.

Given:  
 vf=−30ms   ...   d=64m   …   a=−6.5ms2v_f=-30\frac{m}{s}\ \ \ ...\ \ \ d=64m\ \ \ \ldots\ \ \ a=-6.5\frac{m}{s^2}  
Which equation would you choose to solve for Initial Velocity?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

37.

Given:  
 vi=5ms    …   vf=−4ms    …   a=−1.3ms2v_i=5\frac{m}{s}\ \ \ \ \ldots\ \ \ v_f=-4\frac{m}{s}\ \ \ \ \ldots\ \ \ a=-1.3\frac{m}{s^2}  
Which equation would you choose to solve for time?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

38.

Given:  
 vi=50ms   …    vf=30ms    …   a=−3.5ms2v_i=50\frac{m}{s}\ \ \ \ldots\ \ \ \ v_f=30\frac{m}{s}\ \ \ \ \ldots\ \ \ a=-3.5\frac{m}{s^2}  
Which equation would you choose to solve for displacement (distance) ?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

39.

Given:  
 vi=18ms   …    vf=0ms   …    t=8sv_i=18\frac{m}{s}\ \ \ \ldots\ \ \ \ v_f=0\frac{m}{s}\ \ \ \ldots\ \ \ \ t=8s  
Which equation would you choose to solve for acceleration?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step

40.

Given:  
 vi=25ms   …    d=40m    …    t=15sv_i=25\frac{m}{s}\ \ \ \ldots\ \ \ \ d=40m\ \ \ \ \ldots\ \ \ \ t=15s  
Which equation would you choose to solve for acceleration?

a)

 vf=vi+atv_f=v_i+at  

b)

 d=  (vi+vf)2td=\ \ \frac{(v_i+v_f)}{2}t  

c)

 d=vit+12at2d=v_it+\frac{1}{2}at^2  

d)

 vf2=vi2+2adv_f^2=v_i^2+2ad  

e)

Cannot be done in a single step