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z-test & t-test

Total questions: 20

Worksheet time: 28mins

Name
Class
Date
1.

When should you use the t-test? (select all that apply)

a)

When you are testing a proportion/percentage of a population

b)

When you are testing for a mean

c)

When you are given the population standard deviation

d)

When you are ONLY given the sample standard deviation

2.

Hypotheses must have a parameter or statistic such as  x‾, μ, σ, s\overline{x},\ \mu,\ \sigma,\ s  

a)

True

b)

False

3.

You do not need BOTH null and alternate hypotheses when testing

a)

True

b)

False

4.

When testing with  α=0.01\alpha=0.01  you get  p=0.12p=0.12 . Your decision should be 

a)

Reject H0H_0 , there is a significant difference

b)

Accept H_0 , there is NOT a significant difference

c)

Reject H_0 , there is NOT a significant difference

d)

Accept H_0 , there is a significant difference

5.

When testing with  α=0.05\alpha=0.05  you get  p=3.2 E−6p=3.2\ E^{-6} . Your decision should be 

a)

Reject H0H_0 , there is a significant difference

b)

Accept H_0 , there is NOT a significant difference

c)

Reject H_0 , there is NOT a significant difference

d)

Accept H_0 , there is a significant difference

6.

For the t-test one uses __________ instead of σ.

a)

n

b)

s

c)

χ2

d)

t

7.

If you wish to test the claim that the mean of the population is 100, the appropriate alternate hypothesis is

a)

 x‾=100\overline{x}=100  

b)

 μ=100\mu=100  

c)

 μ≠100\mu\ne100  

d)

 μ>100\mu>100  

8.

In a New York modeling agency, a researcher wishes to see if the average height of female models is really less than 67 inches, as the chief claims. A random sample of 20 models has an average height of 65.8 inches. The standard deviation of the sample is 1.7 inches. At \alpha=0.05 , is the average height of the models really less than 67 inches? List test, p-value, and decision.

a)

z-test,  p=0.002p=0.002 , Accept H0H_0 

b)

z-test,  p=7.98E−4p=7.98E^{-4} , Reject H_0 

c)

t-test,  p=0.003p=0.003 , Reject H_0 

d)

t-test,  p=0.005p=0.005 , Reject H_0 

9.
What is the only option for the null hypothesis? 
a)
H0 = k
b)
H0 > k
c)
H0 < k
d)
H0 ≠ k
10.

The weight of the average 6th grade boy is 89 lbs. The principal of the school feeds them steak for first semester to see if their weight changes. What are the null and alternate hypotheses?

a)

H0: μ = 89

H1: μ = 89

b)

H0: μ = 89

H1: μ > 89

c)

H0: μ = 89

H1: μ < 89

d)

H0: μ = 89

H1: μ ≠ 89

11.

Find the critical value(s) for a two-tailed test with α = 0.05

a)

z = -1.64

b)

z = 1.64

c)

z = ±0.06

d)

z = ±1.96

12.

In a recent survey, the average amount of money

students have in their pockets is ₱280.80 with a standard

deviation of ₱62.40. A teacher feels that the average

amount is actually higher. She surveys 80 randomly

selected students and finds the average amount is

₱289. What are the null and alternate hypotheses?

a)

H0: x̄ = ₱280.80

H1: x̄ ≠ ₱280.80

b)

H0: x̄ = ₱280.80

H1: x̄ > ₱280.80

c)

H0: x̄ = ₱280.80

H1: x̄ < ₱280.80

d)

H0: x̄ > ₱280.80

H1: x̄ = ₱280.80

13.

In a recent survey, the average amount of money

students have in their pockets is ₱120.40 with a standard

deviation of ₱57.20. A teacher feels that the average

amount is actually higher. She surveys 80 randomly

selected students and finds the average amount is

₱254.50. Which test should be used?

a)

z-test

b)

t-test

c)

z-test for proportion

d)

χ2-test

14.

In a recent survey, the average amount of money

students have in their pockets is $5.40 with a standard

deviation of $1.20. A teacher feels that the average

amount is actually higher. She surveys 80 randomly

selected students and finds the average amount is

$5.50. At α = 0.05, what is the p-value for this test?

a)

p = 0.456

b)

p = 0.772

c)

p = 0.228

d)

p = 0.229

15.

In a recent survey, the average amount of money

students have in their pockets is $5.40 with a standard

deviation of $1.20. A teacher feels that the average

amount is actually higher. She surveys 80 randomly

selected students and finds the average amount is

$5.50. At α = 0.05, do we accept or reject the null hypothesis?

a)

Accept H0

b)

Reject H0

16.

In a recent survey, the average amount of money

students have in their pockets is $5.40 with a standard

deviation of $1.20. A teacher feels that the average

amount is actually higher. She surveys 80 randomly

selected students and finds the average amount is

$5.50. At α = 0.05, test the teacher’s claim that the

average amount of money is actually higher than $5.40.

a)

There is enough evidence to reject the claim

b)

There is not enough evidence to reject the claim

c)

There is enough evidence to support the claim that the average amount of money is higher

d)

There is not enough evidence to support the claim that the average amount of money is higher

17.

The average cost of a speeding ticket is $155. The population standard deviation is $10.78. A random sample of 35 speeding ticket court cases showed that the mean cost was $152.59. At the 0.05 significance level, is that less than $155?

a)

Yes, there is a significant difference

b)

Yes, there is not a significant difference

c)

No, there is a significant difference

d)

No, there is not a significant difference

18.
A P-value indicates:
a)
the probability that the null hypothesis is true
b)
the probability that the alternative hypothesis is true
c)
the probability of obtaining the results (or one more extreme) if the null hypothesis is true
d)
probability of a Type I error
19.
A car manufacturer advertises that its new subcompact models get an mean of 47 mpg. If μ is the mileage of these cars, what could be the null and alternate hypothesis if we wanted to check if the car's mpg is overrated? 
a)
H0 p= 47
Ha = 47
b)
H0 µ= 47
Ha < 47
c)
Ha p= 47
Ha > 47
d)
Ha µ= 47
Ha ≠ 47
20.

A real estate agent believes that the average closing cost of purchasing a new home is $6500. She selects 40 new home sales at random and finds that the average closing costs are $6600. The standard deviation of the population is $120. Test her belief at α=0.05\alpha=0.05 . List test, p-value, and decision.

a)

z-test,  p=1.36E−7p=1.36E^{-7} , Reject  H0H_0  

b)

z-test,  p=6.81E−8p=6.81E^{-8} , Accept H_0  

c)

t-test,  p=5.32E−6p=5.32E^{-6}  , Reject H_0  

d)

t-test,  p=2.66E−6p=2.66E^{-6}  , Accept H_0