Worksheetsz-test & t-test
Total questions: 20
Worksheet time: 28mins
When should you use the t-test? (select all that apply)
When you are testing a proportion/percentage of a population
When you are testing for a mean
When you are given the population standard deviation
When you are ONLY given the sample standard deviation
Hypotheses must have a parameter or statistic such as x, μ, σ, s
True
False
You do not need BOTH null and alternate hypotheses when testing
True
False
When testing with α=0.01 you get p=0.12 . Your decision should be
Reject H0 , there is a significant difference
Accept H0 , there is NOT a significant difference
Reject H0 , there is NOT a significant difference
Accept H0 , there is a significant difference
When testing with α=0.05 you get p=3.2 E−6 . Your decision should be
Reject H0 , there is a significant difference
Accept H0 , there is NOT a significant difference
Reject H0 , there is NOT a significant difference
Accept H0 , there is a significant difference
For the t-test one uses __________ instead of σ.
n
s
χ2
t
If you wish to test the claim that the mean of the population is 100, the appropriate alternate hypothesis is
x=100
μ=100
μ=100
μ>100
In a New York modeling agency, a researcher wishes to see if the average height of female models is really less than 67 inches, as the chief claims. A random sample of 20 models has an average height of 65.8 inches. The standard deviation of the sample is 1.7 inches. At α=0.05 , is the average height of the models really less than 67 inches? List test, p-value, and decision.
z-test, p=0.002 , Accept H0
z-test, p=7.98E−4 , Reject H0
t-test, p=0.003 , Reject H0
t-test, p=0.005 , Reject H0
The weight of the average 6th grade boy is 89 lbs. The principal of the school feeds them steak for first semester to see if their weight changes. What are the null and alternate hypotheses?
H0: μ = 89
H1: μ = 89
H0: μ = 89
H1: μ > 89
H0: μ = 89
H1: μ < 89
H0: μ = 89
H1: μ ≠ 89
Find the critical value(s) for a two-tailed test with α = 0.05
z = -1.64
z = 1.64
z = ±0.06
z = ±1.96
In a recent survey, the average amount of money
students have in their pockets is ₱280.80 with a standard
deviation of ₱62.40. A teacher feels that the average
amount is actually higher. She surveys 80 randomly
selected students and finds the average amount is
₱289. What are the null and alternate hypotheses?
H0: x̄ = ₱280.80
H1: x̄ ≠ ₱280.80
H0: x̄ = ₱280.80
H1: x̄ > ₱280.80
H0: x̄ = ₱280.80
H1: x̄ < ₱280.80
H0: x̄ > ₱280.80
H1: x̄ = ₱280.80
In a recent survey, the average amount of money
students have in their pockets is ₱120.40 with a standard
deviation of ₱57.20. A teacher feels that the average
amount is actually higher. She surveys 80 randomly
selected students and finds the average amount is
₱254.50. Which test should be used?
z-test
t-test
z-test for proportion
χ2-test
In a recent survey, the average amount of money
students have in their pockets is $5.40 with a standard
deviation of $1.20. A teacher feels that the average
amount is actually higher. She surveys 80 randomly
selected students and finds the average amount is
$5.50. At α = 0.05, what is the p-value for this test?
p = 0.456
p = 0.772
p = 0.228
p = 0.229
In a recent survey, the average amount of money
students have in their pockets is $5.40 with a standard
deviation of $1.20. A teacher feels that the average
amount is actually higher. She surveys 80 randomly
selected students and finds the average amount is
$5.50. At α = 0.05, do we accept or reject the null hypothesis?
Accept H0
Reject H0
In a recent survey, the average amount of money
students have in their pockets is $5.40 with a standard
deviation of $1.20. A teacher feels that the average
amount is actually higher. She surveys 80 randomly
selected students and finds the average amount is
$5.50. At α = 0.05, test the teacher’s claim that the
average amount of money is actually higher than $5.40.
There is enough evidence to reject the claim
There is not enough evidence to reject the claim
There is enough evidence to support the claim that the average amount of money is higher
There is not enough evidence to support the claim that the average amount of money is higher
The average cost of a speeding ticket is $155. The population standard deviation is $10.78. A random sample of 35 speeding ticket court cases showed that the mean cost was $152.59. At the 0.05 significance level, is that less than $155?
Yes, there is a significant difference
Yes, there is not a significant difference
No, there is a significant difference
No, there is not a significant difference
Ha = 47
Ha < 47
Ha > 47
Ha ≠ 47
A real estate agent believes that the average closing cost of purchasing a new home is $6500. She selects 40 new home sales at random and finds that the average closing costs are $6600. The standard deviation of the population is $120. Test her belief at α=0.05 . List test, p-value, and decision.
z-test, p=1.36E−7 , Reject H0
z-test, p=6.81E−8 , Accept H0
t-test, p=5.32E−6 , Reject H0
t-test, p=2.66E−6 , Accept H0
