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WorksheetsConics - Parabolas
Total questions: 25
Worksheet time: 47mins
When the x-part is squared, the parabola opens up or down.
What are the coordinates for the focus? x+1=−81(y−4)2
(1,4)
(−1,6)
(−1,2)
(−3,4)
What is the equation of the directrix? x+5=41(y+3)2
y=4
x=2
y=−4
x=−6
Which direction does this parabola open?
x−2=−41(y+1)2
Up
Down
Left
Right
Which equation below represents a parabola that opens upward with a vertex at (0,−5) ?
y−5=x2
y+5=x2
y=(x−5)2
y=(x+5)2
What is the green dashed line called?
directrix
parabola
axis of symmetry
asymptote
What is the axis of symmetry for a parabola that opens right with a vertex at (−3,2) .
y=−2
x=3
x=−3
y=2
What is the equation of the directrix? y+5=41(x+3)2
x=4
x=2
y=−4
y=−6
What is the "p-value" in the equation?
x+4=−401(y−9)2
−10
10
−40
40
What is the coordinate of the vertex?
x+1=−81(y−4)2
(1,4)
(−1,−4)
(1,−4)
(−1,4)
What is the coordinate of the vertex?
y+5=41(x+3)2
(3,5)
(−3,−5)
(5,3)
(−5,−3)
What is the value of p?
x−6=121y2
12
48
4
3
Where is the axis of symmetry for this parabola?
x=−1
x=0
y=3
x=−3
If the directrix is y=4 and the focus is at
(3,0) , the vertex is:
(3,4)
(3,2)
(3.5, 0)
(0, 3.5)
True or False?
When the y-part is squared, the parabola opens up or down.
True
False
This is a ___________ parabola that opens _________.
y−11=401(x−5)2
vertical: up
vertical: down
horizontal: to the right
horizontal: to the left
What is the domain and range of the given parabola?
y+1=6(x−4)2
Domain: All Real Numbers
Range: y≥−1
Domain: x≥−1
Range: All Real Numbers
Domain: All Real Numbers
Range: y≤4
Domain: x≥4
Range: All Real Numbers
What is the axis of symmetry for a parabola that has a vertex at (−3,2) and a focus at (−3,−1)
y=−2
x=3
x=−3
y=2
Convert to vertex form.
y=−2x2+24x+5
y+6=−2(x+12)2
y+31=−2(x−12)2
y+77=−2(x−6)2
y+31=−2(x−6)2
Convert the equation to vertex form.
y2+x+4y+1=0
x+3=−(y−2)2
x−3=(y+2)2
x−3=−(y+2)2
none of these
Bonus time!
If the focus is at (2,0) and the directrix is at x=−10 what is the equation of the parabola?
(x+4)=241y2
x=−121(y+4)2
y+4=161x2
y=−201(x+4)2
