WorksheetsWord problems Please do by making equation
Total questions: 25
Worksheet time: 1hrs 8mins
1. Solve x + 2y = 8 and x + y = 5 and find the value of x and y.
x=2 and y= 3
x=3 and y=2
x= 4 and y=2
x= - 2 and y=5
The sum of two numbers is 45. If the greater number is 9 more than the smaller one, find the numbers
27 and 18
36 and 9
21 and 24
19 and 26
1. The total cost of 3 kg of apples and 5 kg of oranges is Rs 245. If the cost of 5 kg of apples is the same as the cost of 8 kg of oranges, find the rate of cost of these fruits.
APPLES= RS 40/KG & ORANGE = RS 25/KG
APPLES= RS 15/KG & ORANGE = RS 40/KG
APPLES= RS 50/KG & ORANGE = RS 19/KG
APPLES= RS25/KG & ORANGE = RS 34/KG
In a fraction, the numerator is 1 less than the denominator. If 1 is added to the numerator and 5 to the denominator, the fraction becomes 21 .Find the original fraction.
54
32
108
64
1. The monthly income of Ram and Hari are in the ratio of 3: 2 and their expenses are in the ratio of 5: 3.If each of them saves Rs 1000 in a month, find their monthly incomes.
Ram = Rs 6000 & Hari = Rs 4000
Ram = Rs 7500 & Hari = Rs 5000
Ram = Rs 3900 & Hari = Rs 2600
Ram = Rs 6600 & Hari = Rs 4400
1. Two years ago, father was 6 times as old as his son was. Three years hence he will be 5 years older than 3 times the age of his son .Find their present ages.
32 yrs & 7 yrs
38 yrs & 8 yrs
44 yrs &9 yrs
22 yrs & 6yrs
1. A year hence a father will be 5 times as old as his son. Two years ago, he was three times as old as his son will be four years hence. Find their present ages.
29 yrs & 5 yrs
34 yrs & 6 yrs
19yrs & 4 yrs
39 yrs & 7 yrs
1. The sum of the digits of a two-digits number is 8. If 18 is subtracted from the number, the places of the digits are interchanged. Find the number.
53
35
62
42
1. The ratio of the present age of A and B is 2: 7. Five years hence, the ratio of their ages will be 3: 8. Find their present ages.
A = 10 yrs & B = 35 yrs
A = 12 yrs & B =42 yrs
A = 8 yrs & B = 28 yrs
A = 6 yrs & B =21 yrs
A two digits number is 3 times the sum of its digits. The sum of the number formed by reversing its digits and 9 is equal to 3 times the original number. Find the number.
27
72
24
36
Mr. Poudel was four times as old as his son was in 2002 but he was only three times as old as his son in 2007 . What is the year of the son’s birth?
1992
1993
1994
11991
When the age of Anup was equal to the present age of Prithak , he was thrice as od as prithak was .If the sum of the present ages of Anup and Prithak is 40 years, find the present age of Prithak.
15 yrs
14yrs
13 yrs
16yrs
1. Amrit started his cycle journey from Bharatpur to Butwal at 7 a.m. with an average speed of 40 km/hr. An hour later Sahaj also started his journey from Bharatpur to Butwal with a uniform speed of 60 km/hr. At what time would they meet each other?
10 am
11 am
10.30 am
9 am
A few number of students are made to stand in rows. If 5 more students were kept in each row, there would be 3 rows less. If 5 less students were kept in each row, there would be 5 rows more. Find the number of students.
300
250
450
500
1 Two buses were coming from two villages situated just in the opposite direction. The uniform speed of one bus is 10 km/hr more than that of another one and they had started their travelling in the same time. If the distance between the villages is 450 km and they meet after 5 hours, find the speed of fast bus.
50 km/hr
40 km/hr
60 km/hr
90 km/hr
The problems are supposed to be solved .......
By making two equations.
By hit and trial method.
Both some by Ist option & some by 2nd option
By inspection
On Monday Nirajan bought 10 cups of Coffee and 5 Doughnuts for his office at the (total) cost of $16.50. It turns out that the doughnuts were more popular than the coffee. On Tuesday he bought 5 cups of Coffee and 10 Doughnuts for a total of $14.25. Which equations could be used to determine the cost of the coffee?
10c + 5d = 14.25
5c + 10d = 16.50
10c + 5d = 16.50
5c + 10d = 14.25
c + d = 10
5c + 10d = 16.50
10c + 5d = 16.50
5c + 5d = 14.25
Roshlin is 3 years younger than twice Prithak's age. The sum of their ages is 33 years. How old are Roshlin and Prithak. If x=Roshlin's age and y=Prithak's age, choose the system that matches the situation.
x + y = 33
y = 2x - 3
x + y = 33
x = 2y - 3
x + y = 33
x = 3 - 2y
x + y = 3
x = 33 - 2y
4x + 2y = 44
x + y = 44
4x = y + 15
x - y = 15
Prithak won a bag full of money! He has 49 bills in all. He counts Rs1430. There are twenty rupees bills and fifty rupees bills. How many of each bill does Prithak have? Which system best represents the situation?
x + y = 1430
20x + 50y = 49
x + y = 49
10x + 5y = 1430
x + y = 49
20x + 50y = 1430
x + y = 49
x + y = 1430
4x + 2y = 44
x + y = 44
4x = y + 15
x - y = 15
Rohan's teacher, Mr.Subedi is eight years younger than five times his age. The sum of their ages is 64. Which equation can be used to find Rohan's age?
6x - 8 = 64
5x - 8 = 64
4x - 8 = 64
5x + 8 = 64
Bhawana's Grandmother is twelve years older than six times her age. The sum of their ages is 117. Which equation can be used to determine Bhawana's age?
6x - 12 = 117
7x - 12 = 117
7x + 12 = 117
6x + 12 = 117
