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WorksheetsDifferential Equations
Total questions: 25
Worksheet time: 42mins
Given the differential equation dP/dt=5P
A) Find the general solution for P to the differential equation
B)Find the particular solution for P to the differential equation given P(0)= 418
A) P=Ce5t
B) P= 5e418t
A) P=Ce5t
B) P= 418e5t
A) P=Cet
B) P= 418et
A) P=Ce10t
B) P= 418e10t
dy/dx = 2x/e2y find the general solution
y = ln (2x/2 + C)
2
y = ln(2x/2)+c
y = e2x+c
y = mx+b
dy/dx= x √y
Find the general solution
√y = ln|4x| + c
√y = (x)-1 + c
2y1/2 = ln|x| + c
1/2y1/2 = ln|x| + c
dy/dx = 4x/y. Suppose y(0)=1
The particular solution is
B
C
D
E
Find the particular solution for y if dy/dx = 2x√y and y = 4 when x = 3.
2√y = x2 + C
y = (x2 + 25)2/4
y = (x2/2-5/2)1/2
y = x4/4
it is number of the highest degree in a differential equation
variable
degree
order
derivative
The power of the differential equation's highest derivative, after the equation has been made rational and integral in all of its derivatives
order
degree
exponent
variable
in dydx , which is the dependent variable?
x
y
d
secret
The following Differential Equation is
dxdy=y2+xy2
Separable.
Non Separable.
Differential equation of the curve y=Acosx-Bsinx, where A and B are arbitrary constant is
y" +xy=0
y"-y=0
y"+y=0
y"+x=0
Integrating factor of the differential equation xdxdy−y=sinx
−x1
x1
ln∣x∣
x21
The solution of linear differential equation xdxdy+2y=x2
y=4x2x2+c
y=4x2+c
y=x2x4+c
y=4x2x4+c
The solution of linear differential equation dxdy+y=ex
y=4x2e2+c
y=4ex2+c
y=x2e4x+c
y=2ex+Ce−x
Order and degree of the D.E. y''+logy'''-xy+(y''')3=0
3,1
2,3
order -3,degree not defined
3,3
The degree of a differential equation is define by a
Positive real number
Positive rational number
Positive integer
All the above
Solution of a linear differential equation of first order can be obtain by
multiplying on both the sides by its integrating factor.
adding on both the sides by integrating factor.
subtracting integrating factor from both sides
None of the above
Solve the differential equation
sec2xtanydx+sec2ytanxdy=0
-sinx tany=c
sinx tany=c
tanx tany=c
-tanx tany=c
Solve the differential equation at x=1,y=0
dy/dx =1+x+y+xy
log|1-y| =x+x2/2 -3/2
log|1+y| =2x+x2/2 -3/2
log|1+y| =x+x2/2 -3/2
log|1+y| =x+x2/2 +3/2
Solve the differential equation
(x-y)dy-(x+y)dx=0
tan-1(y/x)+(1/2)log|x2+y2|+c
-tan-1(y/x)-(1/2)log|x2+y2|+c
tan-1(y/x)-(1/2)log|x2+y2|+c
tan-1(y/x)-(1/3)log|x2+y2|+c
Solve the differential equation
xdy/dx =y-xtan(y/x)
sin(y/x) =c/x
-sin(y/x) =c/x
cos(y/x) =c/x
tan(y/x) =c/x
Which of the following differential equation is a homogeneous equation of degree 2?
dxdy=2xy
ydxdy=2x
dxdy=xy3xy+y2
xydxdy=y2−1
Which of the following differential equations can be classified as separable and exact?
y3dx+3xy2dy=0
dxdy=xx+y
dxdy=3(y+5)x
(x2+1)dy+(xy+x)dx=0
The number of bacteria increases at a rate proportional to the present amount. After 5 hours, there were 80 bacteria and after 8 hours, there were 120 bacteria. How many bacteria were present initially?
1
About 16
About 40
About 53
Integrate ∫(cos2x1−sinx)dx
tanx−secx+c
tanx+secx+c
cotx−cosecx+c
cotx+cosecx+c
Evaluate the indefinite integral using integration by parts.
∫3x e2x dx
−2xe2x+4e2x+C
23xe2x−43e2x+C
xe−2x+2(1−x2)+C
−2xe2x+4lne2x+C
