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Тригонометриялық теңдеулер

Total questions: 10

Worksheet time: 10mins

Name
Class
Date
1.

 sinx=a\sin x=a  тригонометриялық теңдеуінің шешімінің жалпы түрі

a)

 x=(1)narcsina+πn, nZx=\left(-1\right)^n\arcsin a+\pi n,\ n\in Z  

b)

 x=±arccosa+2πn, nZx=\pm\arccos a+2\pi n,\ n\in Z  

c)

 x=π2+2πn, nZx=\frac{\pi}{2}+2\pi n,\ n\in Z  

d)

 x=π4+πn, nZx=-\frac{\pi}{4}+\pi n,\ n\in Z  

2.

 cosx=a \cos x=a\   тригонометриялық теңдеуінің шешімінің жалпы түрі

a)

 x=arccosa+πn, nZx=\arccos a+\pi n,\ n\in Z  

b)

 x=±arccosa+2πn, nZx=\pm\arccos a+2\pi n,\ n\in Z  

c)

 x=arccosa+2πn, nZx=\arccos a+2\pi n,\ n\in Z  

d)

 x=π2+2πn, nZx=\frac{\pi}{2}+2\pi n,\ n\in Z  

3.

 tgx=a tgx=a\   теңдеуінің шешімі

a)

 x=arctga+πn, nZx=ar\operatorname{ctg}a+\pi n,\ n\in Z  

b)

 x=arcctga +πn, nZx=\operatorname{arcctg}a\ +\pi n,\ n\in Z  

c)

 x=arctga+2πn, nZx=ar\operatorname{ctg}a+2\pi n,\ n\in Z  

d)

 x=arcctga +2πn, nZx=\operatorname{arcctg}a\ +2\pi n,\ n\in Z  

4.

 ctgx=a\operatorname{ctg}x=a  теңдеуінің шешімі

a)

 x=arctga+πn, nZx=ar\operatorname{ctg}a+\pi n,\ n\in Z  

b)

 x=arctga+2πn, nZx=ar\operatorname{ctg}a+2\pi n,\ n\in Z  

c)

 x=arcctga+πn, nZx=\operatorname{arcctg}a+\pi n,\ n\in Z  

d)

 x=arcctga+2πn, nZx=\operatorname{arcctg}a+2\pi n,\ n\in Z  

5.

 2sinx=12\sin x=1  теңдеуінің шешімі

a)

 x=(1)n π6+πn, nZx=\left(-1\right)^n\ \frac{\pi}{6}+\pi n,\ n\in Z  

b)

 x=(1)n π3+πn, nZx=\left(-1\right)^n\ \frac{\pi}{3}+\pi n,\ n\in Z  

c)

 x=(1)n+1 π3+2πn, nZx=\left(-1\right)^{n+1}\ \frac{\pi}{3}+2\pi n,\ n\in Z  

d)

 x=(1)n π6+2πn, nZx=\left(-1\right)^n\ \frac{\pi}{6}+2\pi n,\ n\in Z  

6.

 cosx=32\cos x=\frac{\sqrt{3}}{2}  теңдеуінің шешімі

a)

 x=±π6+2πk, kZx=\pm\frac{\pi}{6}+2\pi k,\ k\in Z  

b)

 x=±π6+πk, kZx=\pm\frac{\pi}{6}+\pi k,\ k\in Z  

c)

 x=±π3+2πk, kZx=\pm\frac{\pi}{3}+2\pi k,\ k\in Z  

d)

 x=±2π3+2πk, kZx=\pm\frac{2\pi}{3}+2\pi k,\ k\in Z  

7.

 tgx=34tgx=\frac{3}{4}  теңдеуінің шешімі

a)

 x=arctg 43+πk, kZx=ar\operatorname{ctg}\ \frac{4}{3}+\pi k,\ k\in Z  

b)

 x=arcctg 34+πk, kZx=\operatorname{arcctg}\ \frac{3}{4}+\pi k,\ k\in Z  

c)

 x=arctg 34+πk, kZx=ar\operatorname{ctg}\ \frac{3}{4}+\pi k,\ k\in Z  

d)

 x=arctg 34+π2k, kZx=ar\operatorname{ctg}\ \frac{3}{4}+\frac{\pi}{2}k,\ k\in Z  

8.

 ctgx=3\operatorname{ctg}x=\sqrt{3}  теңдеуінің шешімі

a)

 x=π6+πn, nZx=\frac{\pi}{6}+\pi n,\ n\in Z  

b)

 x=π6+2πn, nZx=\frac{\pi}{6}+2\pi n,\ n\in Z  

c)

 x=π3+πn, nZx=\frac{\pi}{3}+\pi n,\ n\in Z  

d)

 x=π6+2πn, nZx=\frac{\pi}{6}+2\pi n,\ n\in Z  

9.

 2cos(x3π6)=32\cos\left(\frac{x}{3}-\frac{\pi}{6}\right)=-\sqrt{3}  теңдеуінің шешімі

a)

 x=±π6+π6+2πn, nZx=\pm\frac{\pi}{6}+\frac{\pi}{6}+2\pi n,\ n\in Z  

b)

 x=±5π6+π6+2πn, nZx=\pm\frac{5\pi}{6}+\frac{\pi}{6}+2\pi n,\ n\in Z  

c)

 x=±5π6+π6+6πn, nZx=\pm\frac{5\pi}{6}+\frac{\pi}{6}+6\pi n,\ n\in Z  

d)

 x=±2π3+π3+6πn, nZx=\pm\frac{2\pi}{3}+\frac{\pi}{3}+6\pi n,\ n\in Z  

10.

 4tg(2xπ4)=14tg\left(2x-\frac{\pi}{4}\right)=1  теңдеуінің шешімі

a)

 x=12arctg 14+π8+πk2, kZx=\frac{1}{2}ar\operatorname{ctg}\ \frac{1}{4}+\frac{\pi}{8}+\frac{\pi k}{2},\ k\in Z  

b)

 x=arctg 14+π8+πk2, kZx=ar\operatorname{ctg}\ \frac{1}{4}+\frac{\pi}{8}+\frac{\pi k}{2},\ k\in Z  

c)

 x=12arctg 14+π4+2πk, kZx=\frac{1}{2}ar\operatorname{ctg}\ \frac{1}{4}+\frac{\pi}{4}+2\pi k,\ k\in Z  

d)

 x=arctg 14+π8+πk, kZx=ar\operatorname{ctg}\ \frac{1}{4}+\frac{\pi}{8}+\pi k,\ k\in Z