Worksheets20MA1021-quiz 2
Total questions: 35
Worksheet time: 35mins
The general term an of the sequence 1, -1, 1, -1, ... is
(−1)(n−1)
1(n−1)
2n-1
n1
The limit value of the sequence an = sinn is
0
21
1
∞
The sequence
Oscillatory
Non-convergent
Convergent
Divergent
The series 5-4-1+5-4-1+5-4-1+.... is
Convergent
Oscillatory
Non-convergent
Non-oscillatory
The series
1+21+31+... isConvergent
Non-convergent
Non-divergent
Divergent
The value of
e1
e
e
e1
If
un=n(n+1)(n+2)2n−1 and vn=n21 then n→∞limvnun=−−−−−1
0
∞
2
The nth term of the series4.7.101+7.10.134+10.13.169+... is
n(n+1)(n+2)2n−1
(n+1)(n+4)(n+7)n2
(3n+1)(3n+4)(3n+7)n2
n(n+1)(n+2)n2
If u(n+1)un=2n+22n+1 then n→∞limn[u(n+1)un−1]
2
2−1
21
3−1
For the exponential series e−x=1−x+2!x2−3!x3+... then n→∞limunu(n+1)
0
x
-x
1
If log(1+x)=x−2x2+3x3−... when x=1 is
Divergent
Oscillatory
Convergent
Non-oscillatory
The interval of convergence of the trignometric series cosx=1−2!x2+4!x4−... is
-1<x<1
For all values of x<0
For all values of x>0
For all values of x
The series 1−21+31−... is
Divergent
Conditionally convergent
Absolutely converget
Oscillatory
For the infinite series log21−log31+log41−... find n→∞limun
1
0
-1
∞
Find the limit value and test the series ∑(logn)−2n
Limit value = 0; the series is convergent
Limit value =1/e ; the series is convergent
Limit value = 1/3; the series is convergent
Limit value = 3; the series is divergent
If u(n+1)un=(1+n1)ne then n→∞lim[nlog u(n+1)un]=
-1/2
1/3
-1/3
1/2
A sequence which is monotonic and bounded is called ________
Divergent
Convergent
Infinite
Oscillatory
The nth term of the series 211+32x2+43x4+... is
(n+2)n+1x2n
(n+1)nx(2n−2)
(n+1)n1
(n+1)n+21
The general term an of the infinite sequence 1, 1/2, 1/3,... is
1/(n+2)
2n-1
1/n
2n
If un=(n+1)(n+1)nn and vn=n1 then n→∞limvnun=
2
1/e
0
e
The value of n→∞lim(1+n1)n is
e
1/e
e
e1
The limit value of the sequence an=1+[2/n] is
0
1/2
∞
1
β(3,4)=
∫01x3(1−x)4dx
∫01x2(1−x)3dx
∫01x2(1+x)3dx
∫0∞x2(1−x)3dx
Γ(n+1)=
∫0∞e−xx(n−1)dx
∫01e−xxndx
∫02πe−xxndx
∫0∞e−xxndx
Γ(29)=
16105π
415π
8105π
15/16
β(5,6)=
1/126
144
1/1260
1/208
∫02πsin3xcos2xdx=
1/15
2/15
1
15π
∫02πsin3xdx
1/3
3π
π
2/3
∫01x2(logx)4dx=
1/3
-3/16
348
34−8
∫∫∫x(l−1)y(m−1)z(n−1)dxdydz=
Γ(l+m+n+1)Γ(l)Γ(m)Γ(n)
Γ(l)Γ(m)Γ(n)
Γ(l+m+n)Γ(l)Γ(m)Γ(n)
Γ(l+m+n+1)1
The volume of the solid generated by the revolution about the y-axis of the area bounded by the
curve x=f(y), the y-axis is
V=∫y2dx
V=∫πy2dx
V=∫πx2dy
V=∫πydx
The function f(x) = tanx is a periodic function with period
2π
4π
3π
2π
The formula to evaluate bn in the Fourier series of the function y = f (x) within the interval (−π,π) is
bn=π1∫−ππf(x)cosnxdx
bn=π1∫−ππf(x)sinnxdx
bn=π1∫02πf(x)sinnxdx
bn=π1∫−ππf(x)dx
If a function f (x) = x2 in the interval (0,2π) then a0 is
32π2
0
3π2
38π2
If f (x) = e−x is a function in the interval (−π,π) then a0=
πeπ−e−π
πe−π−eπ
π1−e−2π
π1−e−π
