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log 5x = log (2x+9)\log\ 5x\ =\ \log\ \left(2x+9\right)log 5x = log (2x+9) (a)
log (10−4x)=log (10−3x)\log\ \left(10-4x\right)=\log\ \left(10-3x\right)log (10−4x)=log (10−3x) (a)
2log7−2r=02\log_7-2r=02log7−2r=0 (a)
log (4k−5)=log(2k−1)\log\ \left(4k-5\right)=\log\left(2k-1\right)log (4k−5)=log(2k−1) (a)
log−m+2=4\log-m+2=4log−m+2=4 (a)
log5(x−3)>1\log_5\left(x-3\right)>1log5(x−3)>1
(a)
log6(2x+7)<10\log_6\left(2x+7\right)<10log6(2x+7)<10 (a)
log15(5x−1)≥0\log_{\frac{1}{5}}\left(5x-1\right)\ge0log51(5x−1)≥0
(0.2,0.4]
[0.2,0.4)
(0.2,0.4)
[0.2,0.4]
log5(3x−1)<1\log_5\left(3x-1\right)<1log5(3x−1)<1 (a)
log27 −log22x >2\log_27\ -\log_22x\ >2log27 −log22x >2 (a)
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