WorksheetsHA2 5B Practice
Total questions: 9
Worksheet time: 18mins
The population of a certain town is modeled by the equation
A(3)=2,210(1+0.02)3What was the initial population of the town?
3
2210
0.02
A(3)
The population of a certain town is modeled by the equation
A(3)=2,210(1+0.02)3Is this town's population growing or shrinking?
Growing
Shrinking
The population of a certain town is modeled by the equation
A(3)=2,210(1+0.02)3At what rate is this town increasing?
0.2
0.0002
0.02%
20%
2%
The population of a certain town is modeled by the equation
A(3)=2,210(1+0.02)3Calculate A(3), the number of people in the town after 3 years. Round to the nearest (whole) person.
*type ONLY the number without a label*
(a)
Which of the following formulas should you use for compounded interest (more than once per year)?
A(t)=P(1+r)t
A(t)=P(1+nr)nt
A(t)=Pert
A(t)=Pe−kt
Which of the following formulas should you use for continuously compounded interest?
A(t)=P(1+r)t
A(t)=P(1+nr)nt
A(t)=Pert
A(t)=Pe−kt
You start a culture of 4,500 bacteria. They die at a rate of 12% every hour. You are curious how long it will take for there to be 300 bacteria left. Which of the following equations models this scenario?
4,500=300(0.88)t
300=4,500(0.12)t
300=4,500(0.88)t
300=4,500(1.12)t
You start a culture of 4,500 bacteria. They die at a rate of 12% every hour. How long it will take for there to be 300 bacteria left? Round to the nearest hour.
(a)
The decay constant (k) of Cobolt-60 is 0.1315. Find the half life of Cobolt-60 using the formula
A(t)=Pe−kt
with t in years. Round to the nearest hundredth of a year.
(a)
