Free Printable Latihan Soal Jumlah dan Selisih Trigonometri

1.

Nilai dari $\cos15\degree$ adalah ...

a)

$\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)$

b)

$\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)$

c)

$\frac{1}{4}\left(-\sqrt{2}-\sqrt{6}\right)$

d)

$\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)$

e)

$\frac{1}{2}\left(\sqrt{6}-\sqrt{2}\right)$

2.

Nilai dari $\tan75\degree$ adalah...

a)

$-2+\sqrt{3}$

b)

$-2-\sqrt{3}$

c)

$2+\sqrt{3}$

d)

$2-\sqrt{3}$

e)

$3+\sqrt{2}$

3.

Nilai dari $\cos165\degree$ adalah....

a)

$-\frac{\sqrt{2}+\sqrt{6}}{4}$

b)

$-\frac{\sqrt{2}-\sqrt{6}}{4}$

c)

$\frac{\sqrt{2}+\sqrt{6}}{4}$

d)

$\frac{\sqrt{3}-\sqrt{6}}{4}$

e)

$\frac{\sqrt{3}-\sqrt{6}}{2}$

4.

$\cos105\degree+\cos15\degree=...$

a)

$\frac{1}{2}$

b)

$\sqrt{2}$

c)

1

d)

$\frac{1}{2}\sqrt{2}$

e)

$-\frac{1}{2}\sqrt{2}$

5.

$\sin75\degree\cos15\degree-\cos75\degree\sin15\degree=...$

a)

0

b)

1

c)

$\frac{1}{2}$

d)

$\frac{1}{2}\sqrt{2}$

e)

$\frac{1}{2}\sqrt{3}$

6.

$\cos85\degree\cos55\degree+\sin85\degree\sin55\degree=...$

a)

0

b)

1

c)

$\frac{1}{2}$

d)

$\frac{1}{2}\sqrt{2}$

e)

$\frac{1}{2}\sqrt{3}$

7.

Nilai $\cos\left(\alpha-30\degree\right)$ = ....

a)

$\frac{1}{2}\sqrt{3}\left(\sin\alpha+\cos\alpha\right)$

b)

$\frac{1}{2}\sqrt{3}\left(\cos\alpha-\sin\alpha\right)$

c)

$\frac{1}{2}\left(\sqrt{3}\cos\alpha+\sin\alpha\right)$

d)

$\frac{1}{2}\left(\cos\alpha-\sqrt{3}\sin\alpha\right)$

e)

$\frac{1}{2}\left(\cos\alpha+\sqrt{3}\sin\alpha\right)$

8.

Rumus sinus jumlah dua sudut...

a)

$\sin\ \left(\alpha+\beta\right)=\sin\ \alpha\ \cos\ \beta+\cos\ \alpha\ \sin\ \beta$

b)

$\sin\ \left(\alpha-\beta\right)=\sin\alpha\ \cos\ \beta-\cos\ \alpha\ \sin\ \beta$

c)

$\sin\ \left(\alpha+\beta\right)=\sin\ \alpha\ \cos\ \beta-\cos\ \alpha\ \sin\ \beta$

d)

$\sin\ \left(\alpha-\beta\right)=\sin\ \alpha\ \cos\ \beta+\cos\ \alpha\ \sin\ \beta$

e)

$\sin\left(\alpha+\beta\right)=\sin\alpha\ \sin\beta+\cos\alpha\ \cos\beta$

9.

Rumus tangen jumlah dua sudut...

a)

$\tan\ \left(\alpha+\beta\right)=\frac{\tan\ \alpha-\tan\ \beta}{1+\tan\ \alpha\ \tan\ \beta}$

b)

$\tan\ \left(\alpha+\beta\right)=\frac{\tan\beta+\tan\ \alpha\ }{1+\tan\ \alpha\ \tan\ \beta}$

c)

$\tan\ \left(\alpha+\beta\right)=\frac{\tan\ \alpha+\tan\ \beta}{1-\tan\ \alpha\ \tan\ \beta}$

d)

$\tan\ \left(\alpha-\beta\right)=\frac{\tan\ \alpha-\tan\ \beta}{1+\tan\ \alpha\ \tan\ \beta}$

e)

$\tan\left(\alpha+\beta\right)=\frac{\tan\alpha-\tan\beta}{1-\tan\alpha\ \tan\beta}$

10.

Rumus cosinus selisih dua sudut...

a)

$\cos\ \left(\alpha+\beta\right)=\cos\ \alpha\cos\ \beta+\sin\ \alpha\ \sin\ \beta$

b)

$\cos\ \left(\alpha-\beta\right)=\cos\ \alpha\ \cos\ \beta-\sin\ \alpha\ \sin\ \beta$

c)

$\cos\ \left(\alpha-\beta\right)=\cos\ \alpha\ \cos\ \beta+\sin\ \alpha\ \sin\ \beta$

d)

$\cos\ \left(\alpha+\beta\right)=\cos\ \alpha\ \cos\ \beta-\sin\ \alpha\ \sin\ \beta$

e)

$\cos\ \left(\alpha-\beta\right)=\cos\alpha\ \sin\beta-\sin\alpha\ \cos\beta$

Latihan Soal Jumlah dan Selisih Trigonometri

Total questions: 10

Worksheet time: 20mins

Similar Resources on Wayground