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Biến đổi Laplace thuận

Total questions: 10

Worksheet time: 14mins

Name
Class
Date
1.

 f(t)=1, t≥0f\left(t\right)=1,\ t\ge0  Xác định F(s)

a)

 1s\frac{1}{s}  

b)

 −1s-\frac{1}{s}  

c)

 ss  

d)

 −s-s  

2.

 f(t)=t3, t≥0f\left(t\right)=t^3,\ t\ge0  Xác định F(s)

a)

 6s4\frac{6}{s^4}  

b)

 −6s4-\frac{6}{s^4}  

c)

 6s3\frac{6}{s^3}   

d)

 −6s3-\frac{6}{s^3}  

3.

 f(t)=e3t, t≥0f\left(t\right)=e^{3t},\ t\ge0  Xác định F(s)

a)

 1s−3\frac{1}{s-3}  

b)

 −1s−3-\frac{1}{s-3}  

c)

 1s+3\frac{1}{s+3}   

d)

 −1s+3-\frac{1}{s+3}  

4.

 f(t)=e−3t, t≥0f\left(t\right)=e^{-3t},\ t\ge0  Xác định F(s)

a)

 1s−3\frac{1}{s-3}  

b)

 −1s−3-\frac{1}{s-3}  

c)

 1s+3\frac{1}{s+3}   

d)

 −1s+3-\frac{1}{s+3}  

5.

 f(t)=sin⁡(5t), t≥0f\left(t\right)=\sin\left(5t\right),\ t\ge0  Xác định F(s)

a)

 5s2+25\frac{5}{s^2+25}  

b)

 5s2+5\frac{5}{s^2+5}  

c)

 ss2+25\frac{s}{s^2+25}   

d)

 ss2+5\frac{s}{s^2+5}  

6.

 f(t)=cos⁡(5t), t≥0f\left(t\right)=\cos\left(5t\right),\ t\ge0  Xác định F(s) biết

a)

 5s2+25\frac{5}{s^2+25}  

b)

 5s2+5\frac{5}{s^2+5}  

c)

 ss2+25\frac{s}{s^2+25}   

d)

 ss2+5\frac{s}{s^2+5}  

7.

 f(t)=t.e3t, t≥0f\left(t\right)=t.e^{3t},\ t\ge0  Xác định F(s)

a)

 1(s−3)2\frac{1}{\left(s-3\right)^2}  

b)

 −1(s−3)2-\frac{1}{\left(s-3\right)^2}  

c)

 1(s+3)2\frac{1}{\left(s+3\right)^2}   

d)

 −1(s+3)2-\frac{1}{\left(s+3\right)^2}  

8.

 f(t)=sin⁡(5t).e3t, t≥0f\left(t\right)=\sin\left(5t\right).e^{3t},\ t\ge0  Xác định F(s)

a)

 5(s−3)2+25\frac{5}{\left(s-3\right)^2+25}  

b)

 5(s−3)2+5\frac{5}{\left(s-3\right)^2+5}  

c)

 s−3(s−3)2+25\frac{s-3}{\left(s-3\right)^2+25}   

d)

 s+3(s+3)2+5\frac{s+3}{\left(s+3\right)^2+5}  

9.

 f(t)=cos⁡(5t).e3t, t≥0f\left(t\right)=\cos\left(5t\right).e^{3t},\ t\ge0  Xác định F(s)

a)

 5(s−3)2+25\frac{5}{\left(s-3\right)^2+25}  

b)

 5(s−3)2+5\frac{5}{\left(s-3\right)^2+5}  

c)

 s−3(s−3)2+25\frac{s-3}{\left(s-3\right)^2+25}   

d)

 s+3(s+3)2+5\frac{s+3}{\left(s+3\right)^2+5}  

10.

 f(t)=cos⁡(5t).e−3t, t≥0f\left(t\right)=\cos\left(5t\right).e^{-3t},\ t\ge0  Xác định F(s)

a)

 5(s+3)2+25\frac{5}{\left(s+3\right)^2+25}  

b)

 5(s+3)2+5\frac{5}{\left(s+3\right)^2+5}  

c)

 s−3(s−3)2+25\frac{s-3}{\left(s-3\right)^2+25}   

d)

 s+3(s+3)2+25\frac{s+3}{\left(s+3\right)^2+25}