A particle moves in a straight line .Its displacement , s m , from a fixed point o, at time t seconds , is given by 
s= $t^2$  -4t.when will the particle be at 5 m to the right?

given that s= $t^2$  -8t +5.find the time when particle is at rest

given that s=3 $t^2$ -12t-4.Find the time interval during which the particle move in the positive direction?

the velocity ,v m $s^{-1}$  of a particle moving along a stright line is given by     v = 4t-3 $t^2$ -2,where t seconds is the time after passing a fixed point o.Find the displacement of the particle from o after 2 seconds.

 $s=\ \frac{1}{3}t^3-\frac{3}{2}t^2\ +\ 2t\ +4$  

given that the above,find the values of t when the particle stop momentarily.

 $v\ =t\ ^4-2t^2+\ 8t\ +1$  

given the above,find the initial acceleration of the particle.

A particle moves along a straight line.its acceleration,         a= 4t-3, where t seconds is time after passing through a fixed point o and its initial velocity is given as follows. the initial velocity is 5 $ms^{-1}$  .Find velocity of particle after 2 seconds.

the displacement,s is given by s=8t- $3t^2$  ,moving from fixed point, o.calculate displacement when t= 2

 $s\ =\ 7t\ -3t^2$  

the displacement,s metres , of a particles from a fixed point,o , t seconds after passing o is given as above.calculate distance travelled by 4th second.