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WorksheetsGauss's law
Total questions: 25
Worksheet time: 19mins
Which of the following must be true for a Gaussian surface through which the net flux is zero?
1. There are no charges inside the surface.
2. The net charge enclosed by the surface is zero.
3. The electric field is zero everywhere on the surface.
I only
II only
I and II only
I, II, and III
Spheres A, B, and C are arranged on the xy
xy-axis as shown. What is the electric flux through a Gaussian sphere of radius 80cm
80cm centered on the origin?
−ϵ04q
−ϵ02q
−ϵ0q
ϵ0q
The electrc field at a perpendicular distance from a long, straight current-carrying wire is directly proportional to:
ln(r)
r2
r1
r21
An electron is moving in the direction shown above and is accelerating toward the disk, which has an electric charge. Which of the following makes a correct claim about the electric field produced by the disk and gives evidence to support this claim?
The electric field is to the left, because the electron accelerates to the left.
The electric field is to the right, because the electron accelerates to the left.
The electric field is toward the top of the page, because the electron was originally moving toward the top of the page.
The electric field is toward the bottom of the page, because the electron was originally moving toward the top of the page.
Two negative charges A and B are placed at the corners of equilateral triangle. What is the magnitude of the net electric field at point C?
r22KQ
r23kQ
r2kQ
r25kQ
Two negative charges A and B are placed at the corners of equilateral triangle. What is the magnitude of the net electric field at point C?
r22KQ
r23kQ
r2kQ
r25kQ
What is the S.I unit of Electric Flux?
CNm2
Nm2
m2NC
m2N2C2
Four charges + 8Q, - 3Q +5Q and -10Q are kept inside a closed surface. What will be the outgoing flux through the surface.
26 V-m
0 V-m
10 V-m
8 V-m
A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the electric___________ will remain same.
Electric Field
Electric Charge
Flux
None of above
Net electrostatic field inside a positively charged conductor is (a) .
A rectangular loop is held perpendicular to a uniform E-field (the loop's normal vector, dA, is parallel to the E-field direction). At what angle to its normal does the loop have to be turned through so the electric flux is one half of its original value?
15 degrees
30 degrees
45 degrees
60 degrees
90 degrees
The normal vector to a rectangular loop makes an angle of 35 degrees with the vector describing the direction of an applied electric field. What is the Electric Flux through the loop, given the following data? E = 52,000 N/C, width = 35 cm, length = 75 cm
1.1 x 10^4 Nm*m/C
7.8 x 10^3 Nm*m/C
1.1 x 10^8 Nm*m/C
7.8 x 10^7 Nm*m/C
zero
A charge of magnitude, q, is at the center of a sphere of radius r. What is the electric flux at the surface of the sphere? r = 0.53 m, q = 5.0 x 10^-6 C
5.6 x 10^5 Nm*m/C
6.5 x 10^5 Nm*m/C
7.3 x 10^5 Nm*m/C
1.1 x 10^6 Nm*m/C
1.3 x 10^6 Nm*m/C
You are trying to calculate the e-field outside a positively charged metal sphere of radius R. The Gaussian surface should be what kind of geometrical object?
circle
cylinder
cube
sphere
rectangle
A metal sphere of radius R is given a positive charge, q. What is the electric field at a distance r from the center, where r < R?
0
What is the graph of the electric field for a charged conducting sphere of radius R?
What is the shape and orientation of the Gaussian surface used to find the electric field outside of an infinite plane of charge?
a sphere through the surface
a cube parallel to the surface
a cube through the surface
a cylinder parallel to the surface
a cylinder perpendicular to the surface
The electric field inside a spherical shell of uniform surface charge density is
Constant, less than zero
Directly proportional to the distance from the centre
zero
None of the above
Figure shows the electric lines of force emerging from a charged body. If the electric field at A and B are EA and EB respectively and if the displacement between A and B is r then
EA > EB
EA < EB
EA = EB / r
EA = EB / r2
An electron and a proton are in a uniform electric field, the ratio of their accelerations will be
Zero
Unity
The ratio of the masses of proton and electron
The ratio of the masses of electron and proton
The distance between the two charges 25 μ C and 36 μ C is 11 cm At what point on the line joining the two, the intensity will be zero
At a distance of 5cm from 25 μ C
At a distance of 5cm from 36 μ C
At a distance of 10cm from 25 μ C
At a distance of 11 cm from 36 μ C
There is a solid sphere of radius ‘R’ having uniformly distributed charge. What is the relation between electric field ‘E’ (inside the sphere) and radius of sphere ‘R’ is
E∝R−2
E∝R−1
E∝R2
E∝R31
Define electric field strength
rate of flow in charge
force per unit positive charge on a stationary charge
potential difference per unit separation between plates
product of force and charge
