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WorksheetsM6 - Quiz reviewer
Total questions: 25
Worksheet time: 1hrs 16mins
In both magnetism right hand rule and ‘rey-gun’ right hand rule; your ‘thumb finger’ represents:
Force
magnetic field strength
current
magnetic flow
Using right-hand rule ‘rey-gun’; if your ‘thumb finger’ is downward and your ‘pointing finger’ is pointing away from your body; then your ‘middle finger’ is pointing in what direction?
towards right
towards left
towards your body
upward
Every magnet usually have its own ____ which usually emitted from north towards south pole.
magnetic force
magnetic current
magnetic strength
magnetic field
The term ‘EMF’ also stands for:
Electric Magnetic Field
Electromotive Force
Elevated Massive Frequency
Electrometric Field
What will be produced whenever you placed a wire-loop inbetween magnet, it will tend to rotate and cut through magnetic field?
EMF
induced voltage
induced current
all of the above
When dealing with charges in an object’s atom, the scientist concluded that it is considered “neutral” whenever:
amount of one charge will greatly deduce the other charge
amount of negative charge balances with the amount of positive charge
amount of positive charge will omit the sign of negative charge regardless of its amount
amount of negative charge will ignore the amount of positive charge
In magnetism, the same pole facing each other will cause: (word starts with letter " r " )
(a)
In magnetism, different poles facing each other will cause:
(a)
Using your right-hand as representation for electrical field, if you hold a pen and your thumb was in upright position then pointing towards your body. The directional flow of your electrical field will be:
clockwise
perpendicular
counter-clockwise
neutral
When calculating of magnetic force/strength of particle charge (fake baby); constant ‘q’ means you are dealing with:
negative particles
single particle
compound particles
multiple particles
You are calculating for Magnetic force due to the movement of particle charge. Whenever you are dealing about wire induced with current that travels upward throughout its length, and subjected to a magnetic field travelling towards East. Then your ‘sin(Ɵ)’ should be equals to (hint: filbis no?):
0.05
1.05
1
0
You are calculating for Magnetic force due to the movement of particle charge. Whenever you are dealing about wire induced with current that travels upward throughout its length, and subjected to a magnetic field travelling parallel in same direction. Then your ‘sin(Ɵ)’ should be equals to (hint: filbis no?):
0.05
1.05
1
0
Calculate for distance of interest point (r); given: magnetic field strength (B) = 3.4 x 10-4 T; ₼o = 4π x 10-7 Tm/A; current (I) = 12 A (hint: boy tutor!)
4.2 x 10-11 Tm
7.01 x 10-3 m
217 m
0.01 m
Calculate for magnetic field strength (B) ; if distance of interest point (r) = 2.5 m; ₼o = 4π x 10-7 Tm/A; current (I) = 8 A (hint: boy tutor!)
3.8 x 10-5 m
5.02 x 10-8 m
6.4 x 10-7 m
2.7 x 10-6 m
Calculate for current (I); if distance of interest point (r) = 3 m; magnetic field strength (B) = 2.5 x 10-4 T; ₼o = 4π x 10-7 Tm/A; (hint: boy tutor!)
8 A
14.67 A
3750 A
2.48 x 10-3 A
Calculate for magnetic force (F); given: magnetic strength (B) = 2.4 x 10-3 T; length of wire (L) = 18 m; current (I) = 13 A; angle (q) = 30° (hint: filbis no?)
2.3 N
1.06 N
21.5 N
0.2808 N
Calculate for length of wire (L); if magnetic force (F) = 0.25 N; magnetic strength (B) = 1.8 x 10-3 T; ; current (I) = 12 A; angle (q) = 22° (hint: filbis no?)
31 m
15.7 m
4.06 m
1.034 m
Calculate for magnetic strength (B); given: magnetic force (F) = 0.80 N/m; current (I) = 34 A (hint: filby!)
1.04 T
0.81 T
0.02 T
2.06 x 10-3 T
Calculate for magnetic force (F); given: magnetic strength (B) = 0.07 T; length of wire (L) = 2.1 m; current (I) = 18 A
2.646 N
0.48 N
5.2 N
10 N
Calculate for current (I); if magnetic force (F) = 4 N; magnetic strength (B) = 1.9 T; length of wire (L) = 1.5 m:
11.4 A
1.14 A
1.4 A
4.11 A
What would be the effective voltage (Veff), if the maximum voltage is 130 V
91.91 V
183.8 V
5.43 V
7.1 V
What would be the effective current (Ieff), if the maximum current is 50 A
12.12 A
35 A
23.7 A
14.2 A
What would be the maximum current, if the effective current (Ieff) is 28 A:
39.6 A
24.5 A
19.8 A
5.7 A
Calculate for Electromagnetic force (VEMF), given: magnetic strength (B) = 0.4 T; wire length (L) = 0.7 m; current flow velocity (v) = 12 m/s
0.047 V
3.36 V
8 V
0.02 V
Calculate for magnetic strength (B), given: wire length (L) = 1.2 m; current flow velocity (v) = 6.2 m/s; Electromagnetic force (VEMF) = 8 V
59.52 T
1.08 T
5.3 T
0.93 T
