NEW
Font size
WorksheetsINDEFINITE INTEGRAL
Total questions: 26
Worksheet time: 4hrs 20mins
∫(x4+3x2+1)Tan−1(xx2+1)x2−1 dx is equal to
Tan−1(x+x1)+c
loge(Tan−1(x+x1))+c
loge(tan(xx2+1))+c
(x+x1)Tan−1(x+x1)+c
The value of the integral ∫sin2x+sin4xcos3x+cos5xdx is
sinx−6Tab−1(sin x)+c
sinx−2(sinx)−1+c
sinx−2(sinx)−1−6Tan−1(sinx)+c
sinx−2(sinx)−1+5Tan−1(sinx)+c
∫x(1+xex)2x+1dx=loge∣∣∣∣1+xexxex∣∣∣∣+f(x)+c, then f(x) is.
1+xex1
1+xexx
1+xxex
1+exxex
∫(x+1)x(x2+x+1)x−1dx is
Tan−1(xx2+x+1)+c
2Tan−1(xx2+x+1)+c
Tan−1(xx2+x+1)+c
2Tan−1x+x1+1+c
∫x4(x−x3)31dx=
83(x21−1)34+c
−83(x21+1)34+c
−83(x21−1)34+c
−43(1−x21)34+c
If y(x−y)2=x, then ∫x−3ydxequals
2xloge{(x−y)2+−1}+c
21loge{(x−y)2−1}+c
x+21loge{(x−y)2+1}+c
loge{(x−y)2−1}+c
If ∫(1+x1−x)21 xdx=2 cos−1x−ϕ(x)+c , then ϕ(x) equals
loge(x1−1−x)
21loge(x1+1−x)
2loge(x1−1−x)
2loge(x1+1−x)
Let I1=∫(x3+3x+1)31x1+1dx=21(x3+3x+1)32+c and I2=∫1+sin2xsin2xdx=loge(1+sin2x)+c Then
both I1and I2 are correct
both I1 and I2 are not correct
I1is correct and I2 is not
I2 is correct and I1 is not
∫1+x2loge(x+1+x2)dxis
2loge(x+1+x2)+c
loge(x+1+x2)+c
21loge(x+1+x2)+c
21loge(x+1+x2)+c
∫1+tanx+tan2xtanxdx is equal to
x+32Tan−1 3(2tanx+1)+c
x−32Tan−1(32tanx+1)+c
x+31Tan−1(3tanx+1)+c
x−31Tan−1(3tanx+1)+c
∫tan3x+tan2x+tanxtan(4π−x)sec2 xdx equals
−2Tan−11+tanx+cotx+c
2 Tan−1tanx+cotx+c
Tan−1tan x+ cot x+c
−2Tan−1secx+tanx+c
∫(x+x+1)22+xdx equals
x+x+12+c
x+x+1x+c
1+x−x2x+c
1+x+x2x+c
∫(x5+x3+1)32x12+5x9 dx is equal to
(x5+x3+1)2x2+2x+c
2(x5+x3+1)2x10+c
loge(x5+x3+1)+2x7+5x4+c
loge(2x7+5x4+x5+x3+1)+c
If ∫(x4+x+1)23x4−1dx=∫f1(x) dx−∫x4+x+1dx+c then f1(x)is
(x4+x+1)24x3+1
(x4+x+1)2x3(4x+1)
(x4+x+1)2x(4x3−1)
(x4+x+1)2x(4x3+1)
∫(1+x2x2+sin2x) cos2xdxis equal to
tanx−Tan−1x+c
tanx+Sin−1x+c
tan x − Sec−1x+c
cotx−Cot−1x+c
If f : R⟶R is a function such the f(0)=0,f′ (0) = 3 and it satisfies the relation f(3x+y)=3f(x)+f(y) for all x, y x, y ∈R then ∫f(x)dx equals
3x2+3
32x2+3
23x2+c
3x2+c
∫x6+1x4+1dx is equal to
Tan−1x−31Tan−1(x3)+c
Tan−1x+3Tan−1(x3)+
Tan−1x+2Tan−1(x2)+c
Tan−1x−2Tan−1(x2)+c
∫(1+cos2x)1+cos2x+cos4xsin3xdxequals
Cos−1(sec x + cos x) +c
Sin−1(sec x + cos x)+c
Sec−1(sec x + cos x)+c
Tan−1(sec x + tan x)+c
(x2+2x)cos2x−(1+x)sin 2x(1+x)sinxdx=21loge ∣∣∣∣t−1t+1∣∣∣∣+c where t is
(x + 1 cos x - sin x
(x + 1) sin x - cos x
(x + 1) sin x + cos x
(x + 1) cos x + sin x
If f is a real-valued function satisfying the relation 5f(x)+3f(x1)=x+2 for all x=0, then ∫xf (x) dx is.
61(35x3+2x2+3x)+c
161(35x3−2x2+3x)+c
161(35x3+2x2−3x)+c
161(35x3−2x2−3x)+c
∫(x2+1)(x4−1)2x5+x4−2x3+2x2+1dx(x>1)is equal to
loge(x2+1)+21loge(x+1x−1)+c
loge(x2−1x2+1)+loge(x+1x−1)+c
loge(x2−1x2+1)+21loge(x+1x−1)+c
loge(x2+1)+x2+11+21loge(x+1x−1)+c
If f(x)=xand g(x)=ex−1, then ∫(f o g) (x) dx equals
2ex−1−2 Tan−1(ex−1)+c
2(ex−1)−2 Tan−1(ex−1)+c
2ex−1−2 tan(ex−1)+c
2ex−1−2 Tan −1(ex−1)+c
∫x2(x4+1)43dxequals
(x4+1)41+c
−x4(x4+1)41+c
−x3(x4+1)43+c
x4(x3+1)43+c
If ∫(x2+1)2(x+1)x3+3x+2dx =−21loge ∣x+1∣+41loge(x2+1)+f(x)+c then f(x) equals
21 Tan−1x+1+x2x
23Tan−1x−1+x2x
23Tan−1x+1+x2x
23loge∣x∣+1+x2x
If ∫tanx+(cotx)20111−(cotx)2010dx=k1loge ∣∣∣(sinx)k+(cosx)k∣∣∣+c then k is equal to
2010
2011
2012
2013
∫x(xetanx+1)1+xsec2xdx is equal to
loge∣∣∣∣xetanx+1xetanx∣∣∣∣+c
loge∣∣∣∣extan x+1(x+1)etanx∣∣∣∣+c
loge∣∣∣∣xetanx+1extanx+1∣∣∣∣+c
loge∣∣∣∣(x+1)etanx+1xetanx+1∣∣∣∣+c
