wayground logo

Free Printable Worksheets

NEW

Font size

S
M
L
XL
Worksheets

FP2 Integration

Total questions: 15

Worksheet time: 18mins

Name
Class
Date
1.

 fn(x)n +C\frac{f^n\left(x\right)}{n}\ +C  
is the standard result of 

a)

 fn1(x)dx\int_{ }^{ }f^{n-1}\left(x\right)dx  

b)

 f(x)fn(x)dx\int f'\left(x\right)f^n\left(x\right)dx  

c)

 f(x)fn1(x)dx\int_{ }^{ }f'\left(x\right)f^{n-1}\left(x\right)dx  

d)

 fn+1(x)f(x)dx\int f^{n+1}\left(x\right)f'\left(x\right)dx  

2.

 11+x2dx =\int\frac{1}{1+x^2}dx\ =  

a)

 tanh1x+C\tanh^{-1}x+C  

b)

 tan1x+C\tan^{-1}x+C  

c)

 tan1(xa)+C\tan^{-1}\left(\frac{x}{a}\right)+C  

d)

 tanh1(xa)+C\tanh^{-1}\left(\frac{x}{a}\right)+C  

3.

 1a2x2dx=\int\frac{1}{\sqrt{a^2-x^2}}dx=  

a)

 cosh1(xa)+C\cosh^{-1}\left(\frac{x}{a}\right)+C  

b)

 sinh1(xa)+C\sinh^{-1}\left(\frac{x}{a}\right)+C  

c)

 cos1(xa)+C\cos^{-1}\left(\frac{x}{a}\right)+C  

d)

 sin1(xa)+C\sin^{-1}\left(\frac{x}{a}\right)+C  

4.

 tanh x dx=\int\tanh\ x\ dx=  

a)

 ln(cosh x)+C\ln\left(\cosh\ x\right)+C  

b)

 ln (sinh x)+C\ln\ \left(\sinh\ x\right)+C  

c)

 ln (sech x)+C\ln\ \left(\operatorname{sech}\ x\right)+C  

d)

 sech2x + C\operatorname{sech}^2x\ +\ C  

5.

 cosh x sinh4x dx=\int\cosh\ x\ \sinh^4x\ dx=  

a)

 15cosh5x+C\frac{1}{5}\cosh^5x+C  

b)

 sinh5x +C\sinh^5x\ +C  

c)

 15sinh5x+C\frac{1}{5}\sinh^5x+C  

d)

 cosh5x+C\cosh^5x+C  

6.

   1x2+a2dx=\int\ \ \frac{1}{\sqrt{x^2+a^2}}dx=  

a)

 tanh1(xa)+C\tanh^{-1}\left(\frac{x}{a}\right)+C  

b)

 sinh1x+C\sinh^{-1}x+C  

c)

 cosh1x +C\cosh^{-1}x\ +C  

d)

 sinh1(xa)+C\sinh^{-1}\left(\frac{x}{a}\right)+C  

7.

  19+4x2dx=\int\ \frac{1}{\sqrt{9+4x^2}}dx=  

a)

 13sinh1(23x)+C\frac{1}{3}\sinh^{-1}\left(\frac{2}{3}x\right)+C  

b)

 13sinh1(32x)+C\frac{1}{3}\sinh^{-1}\left(\frac{3}{2}x\right)+C  

c)

 13sin1(23x)+C\frac{1}{3}\sin^{-1}\left(\frac{2}{3}x\right)+C  

d)

 13sin1(32x)+C\frac{1}{3}\sin^{-1}\left(\frac{3}{2}x\right)+C  

8.

  cosh1x dx=\int\ \cosh^{-1}x\ dx=  

a)

 x cosh1xx21+ Cx\ \cosh^{-1}x-\sqrt{x^2-1}+\ C  

b)

 x cosh1x+x21+Cx\ \cosh^{-1}x+\sqrt{x^2-1}+C  

c)

 x sinh1x21+Cx\ \sinh^{-1}-\sqrt{x^2-1}+C  

d)

 x cosh1xx2+1x\ \cosh^{-1}x-\sqrt{x^2+1}  

9.

  1x24dx=\int\ \frac{1}{\sqrt{x^2-4}}dx=  

a)

 cosh1(2x)+C\cosh^{-1}\left(2x\right)+C  

b)

 12cosh1(x2)+C\frac{1}{2}\cosh^{-1}\left(\frac{x}{2}\right)+C  

c)

 cosh1(x2)+C\cosh^{-1}\left(\frac{x}{2}\right)+C  

d)

 12cosh1(x)+C\frac{1}{2}\cosh^{-1}\left(x\right)+C  

10.

  14x2+12x40dx=\int\ \frac{1}{\sqrt{4x^2+12x-40}}dx=  

a)

  14(x32)2+49dx\int\ \frac{1}{\sqrt{4\left(x-\frac{3}{2}\right)^2}+49}dx  

b)

   14(x32)249dx\int\ \ \frac{1}{\sqrt{4\left(x-\frac{3}{2}\right)^2-49}}dx  

c)

  12(x+32)249dx\int\ \frac{1}{2\sqrt{\left(x+\frac{3}{2}\right)^2-49}}dx  

d)

  12(x+32)2494dx\int\ \frac{1}{2\sqrt{\left(x+\frac{3}{2}\right)^2-\frac{49}{4}}}dx  

11.

 Solve 1020 14x2+12x40 dxSolve\ \int_{10}^{20}\ \frac{1}{\sqrt{4x^2+12x-40}}\ dx  

a)

3.22

b)

0.322

c)

32.2

d)

322

12.

 Evaluate  02 19x2+4dxEvaluate\ \ \int_0^2\ \frac{1}{\sqrt{9x^2+4}}dx  

a)

 13ln (103)\frac{1}{3}\ln\ \left(\sqrt{10}-3\right)  

b)

 13sinh1(13)\frac{1}{3}\sinh^{-1}\left(\frac{1}{3}\right)  

c)

 13ln (10+3)\frac{1}{3}\ln\ \left(\sqrt{10}+3\right)  

d)

 13cosh1(3)\frac{1}{3}\cosh^{-1}\left(3\right)  

13.

 Given In=0π2 sinnx dx=n1nIn2. Given\ I_n=\int_0^{\frac{\pi}{2}}\ \sin^nx\ dx=\frac{n-1}{n}I_{n-2}.\   

Find  I4I_4   

a)

 316\frac{3}{16}  

b)

 316π\frac{3}{16}\pi  

c)

 815\frac{8}{15}  

d)

 815π\frac{8}{15}\pi  

14.

 The reduction formula for  01 ex(1x)n dx    isThe\ reduction\ formula\ for\ \ \int_0^1\ e^{-x}\left(1-x\right)^n\ dx\ \ \ \ is  


a)

 1+nIn11+nI_{n-1}  

b)

 1n1nIn11-\frac{n-1}{n}I_{n-1}  

c)

 1nIn11-nI_{n-1}  

d)

 1nIn+11-nI_{n+1}  

15.

 Given   In=0π4tannx dx=0π4tann2x tan2 x dx.Given\ \ \ I_n=\int_0^{\frac{\pi}{4}}\tan^nx\ dx=\int_0^{\frac{\pi}{4}}\tan^{n-2}x\ \tan^2\ x\ dx.  



Find the reduction formula for  InI_n  

a)

 1n1In2\frac{1}{n-1}-I_{n-2}  

b)

 1n1In1\frac{1}{n-1}-I_{n-1}  

c)

 1nIn2\frac{1}{n}-I_{n-2}  

d)

 nn1In2\frac{n}{n-1}-I_{n-2}