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WorksheetsFP2 Integration
Total questions: 15
Worksheet time: 18mins
nfn(x) +C
is the standard result of
∫fn−1(x)dx
∫f′(x)fn(x)dx
∫f′(x)fn−1(x)dx
∫fn+1(x)f′(x)dx
∫1+x21dx =
tanh−1x+C
tan−1x+C
tan−1(ax)+C
tanh−1(ax)+C
∫a2−x21dx=
cosh−1(ax)+C
sinh−1(ax)+C
cos−1(ax)+C
sin−1(ax)+C
∫tanh x dx=
ln(cosh x)+C
ln (sinh x)+C
ln (sech x)+C
sech2x + C
∫cosh x sinh4x dx=
51cosh5x+C
sinh5x +C
51sinh5x+C
cosh5x+C
∫ x2+a21dx=
tanh−1(ax)+C
sinh−1x+C
cosh−1x +C
sinh−1(ax)+C
∫ 9+4x21dx=
31sinh−1(32x)+C
31sinh−1(23x)+C
31sin−1(32x)+C
31sin−1(23x)+C
∫ cosh−1x dx=
x cosh−1x−x2−1+ C
x cosh−1x+x2−1+C
x sinh−1−x2−1+C
x cosh−1x−x2+1
∫ x2−41dx=
cosh−1(2x)+C
21cosh−1(2x)+C
cosh−1(2x)+C
21cosh−1(x)+C
∫ 4x2+12x−401dx=
∫ 4(x−23)2+491dx
∫ 4(x−23)2−491dx
∫ 2(x+23)2−491dx
∫ 2(x+23)2−4491dx
Solve ∫1020 4x2+12x−401 dx
3.22
0.322
32.2
322
Evaluate ∫02 9x2+41dx
31ln (10−3)
31sinh−1(31)
31ln (10+3)
31cosh−1(3)
Given In=∫02π sinnx dx=nn−1In−2.
Find I4
163
163π
158
158π
The reduction formula for ∫01 e−x(1−x)n dx is
1+nIn−1
1−nn−1In−1
1−nIn−1
1−nIn+1
Given In=∫04πtannx dx=∫04πtann−2x tan2 x dx.
Find the reduction formula for In
n−11−In−2
n−11−In−1
n1−In−2
n−1n−In−2
