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WorksheetsSpotlight- Precalc Spiral Review
Total questions: 107
Worksheet time: 4hrs 12mins
x2 + 7x - 30
Example: (d2)5
Identify where the function is positive.
−7<x<3, x > 5
x<−7, −3<x<5
x <−7, x >5
−7<x<5
Example: c6 ⋅ c4
x < 3 or x ≥ 5
Example: h8 / h3
Simplify using your exponent rule(s) x⁵⁄x³
x²
x
1
x⁸
Simplify using your exponent rule(s) x⁻⁶
1 ⁄ x⁶
x⁶
-x⁶
-1 ⁄ x⁶
Simplify using your exponent rule(s) -14x7/7x
-2x6
-2x
-2x5
-2x8
Simplify using your exponent rule(s) (53x2y4)0
5xy
1
0
5
Rewrite using positive exponents
24
1/24
42
1/42
Simplify using your exponent rule(s) (2x3y)6
2x18y6
64x18y6
64x3y6
2x3y6
7-10
s-5 ⋅ s-2
x2 + 9x - 36
n2 + 5n - 6
a2 - a - 12
r2 -16r + 60
x2 -16x + 48
p2 - 14p
x2 -15x + 36
x2 - 8x - 128
n2 + 16n + 63
x2 - 8x + 15
x2 - 5x
Factor the following: x2−1
(x+1)(x +1)
(x - 1)(x - 1)
prime
(x + 1)(x - 1)
4x2 - 25
(2x + 5) (2x - 5)
(2x - 5)2
(2x + 5)2
2x + 5(2x - 5)
25x2 - 36y2
5x + 6y(5x - 6y)
(5x + 6y) (5x - 6y)
(5x + 6y)2
(5x - 6y)2
x4 - 100y2
(x2 + 10y) (x2 - 10y)
(x + 10y) (x - 10y)
(x + 10y) (x3 - 10y)
(x3 + 10y) (x - 10y)
We can't factor using difference of two square this
49x2 + 4y2. Why?
Because 4 is not a perfect cubed number.
Because 4 is not a perfect squared number.
Because 49 is not a perfect squared number.
Because we can't factor using difference of two squares if it is addition sign.
Factor:
4x + 6
4(x + 2)
2(2x + 3)
2(2x + 4)
4(x + 2/3)
-8 ≤ x < 8
-9 < x ≤ -4
-9 < x ≤ -4
x < 8
x ≥ 100
Identify where the function is positive.
x<−5 , x>0
−5<x<0 , x>6
x<−5 , 0<x<6
x>−5 , x<6
Identify where the function is negative.
x >−3
All Real Numbers
−3<x<3
x<−3, x>3
Identify where the function is positive.
−3<x<3
All Real Numbers
x<−3, x>3
Identify where the function is negative.
x<−7, x >5
−7<x<−3, x >5
x<−7, −3<x<5
−7<x<5
Identify where the function is increasing.
x <−4 , x >1
− 4<x<1
−6<x<−2
x<−6 , x >−2
Identify where the function is decreasing.
x < -5 , x > -1
-5 < x < 1 , x > 8
x < -5 , -1 < x < 8
All Real Numbers
Identify where the function is increasing.
x < 0
x > 0
x < -3 , x > 3
-3 < x < 3
Describe the transformation that occurred
p(x) = f(x + 3)
Right 3 units
Vertical Stretch
Up 3 units
Left 3 units
Describe the transformation that occurred.
h(x) = f(x) + 2
up 2 units
left 2 units
Vertical Strech
right 2 units
Describe the transformation that occurred.
w(x) = f(x - 7)
Down 7
Up 7
Right 7
vertical compression
Describe the transformation that occurred
m(x) = f(x + 1)
Left 1 Unit
Right 1 unit
vertical stretch
up 1 unit
Describe the transformation that occurred
k(x) = f(x) - 9
vertical compression
Down 9 units
Left 9 units
Right 9 Units
Describe the transformation that occurred
g(x) =2f(x)
Up 2 units
vertical compression
vertical stretch
Right 2 Units
Describe the transformation that occurred
h(x) = 1/5f(x)
Up 5 Units
vertical compression
vertical stretch
Down 5 Units
Describe the transformation that occurred
t(x) = f(x) - 1
Right 1 Unit
Down 1 Unit
vertical compression
vertical stretch
Describe the transformation that occurred
s(x) = 7f(x)
vertical compression
Up 7 Units
Over 7 Units
vertical stretch
d(x) = f(x) - 1
0.5f(x)
vertical compression
vertical stretch
vertical shift up 3
vertical shift down 3
3f(-x)
reflection over x-axis, vertical compression
reflection over y-axis, vertical stretch
reflection over x-axis, horizontal compression
reflection over y-axis, horizontal stretch
¼f(x) + 1
vertical stretch, shift up 1
vertical compression, shift up 1
vertical stretch, shift up ¼
vertical compression, shift down ¼
-f(x) + 2
horizontal reflection, translation up 2
vertical reflection, translation up 2
vertical reflection, translation right 2
vertical reflection, translation down 2
¾f(x − 7)
vertical compression, translation right 7
vertical stretch, translation down 7
vertical compression, translation left 7
vertical stretch, translation right 7
Write in function form: translation 3 units right
g(x) = f(x − 3)
g(x) = f(x) − 3
g(x) = -3f(x)
g(x) = f(-3x)
vertical compression
2f(x)
f(½x)
½f(x)
f(2x)
reflection over y-axis, shift right 1
f(-x - 1)
-f(x + 1)
-f(x) - 1
-f(x - 1)
translation up 1
f(x) + 1
f(x - 1)
f(x) - 1
f(x + 1)
vertical stretch, translation left 3
½f(x + 3)
4f(x - 3)
4f(x) + 3
4f(x + 3)
vertical reflection, horizontal stretch
g(x) = ½f(-x)
g(x) = -f(¼x)
g(x) = -3f(x)
g(x) = -f(4x)
horizontal compression
g(x) = 3f(x)
g(x) = ½f(x)
g(x) = f(¼x)
g(x) = f(5x)
horizontal compression, translation up 3
f(4x) + 3
4f(x) - 3
4f(x) + 3
f(4x) - 3
y=(x-2)3+4
