NEW
Font size
WorksheetsAP Statistics Spring Semester Review
Total questions: 70
Worksheet time: 1hrs 23mins
What is the mean of the sampling distribution of p-hat?
What is the standard deviation of the sampling distribution?
According to the Center for Disease Control, 93% of children entering kindergarten in the U.S. are vaccinated. A school district has 180 incoming kindergarten children.
Which of the following is true concerning the shape of the sampling distribution?
The sampling distribution is normal because n > 30
The sampling distribution is not normal because nq is < 30
The sampling distribution is normal because 10% of 180 is > 10
The sampling distribution is normal because np and nq are both > 10
According to a television commercial, 3 out of 4 dentists recommend Trident gum for patients who have dental work. A consumer magazine has surveyed 100 dentists to see if this claim is true.
Which is closest to the probability that between 70 and 74 percent of the dentists recommend Trident?
.9238
.2846
-.2846
.0762
A researcher plans to use a random sample of families to estimate the mean monthly family income for a large population. The researcher is deciding between a 95% confidence level and a 99% confidence level. Compared to a 95% confidence interval, a 99% confidence interval will be…
It would be narrower because it omits only 1% of the possible samples instead of 5%
It would be wider because it has a higher confidence, which requires a larger margin of error.
It would be narrower because it has a higher confidence, which requires a larger margin of error.
It would be the same because the sample is the same.
You can’t tell because the margin of error varies from sample to sample.
The Gallup Poll interviews 1600 people. Of these, 18% say that they jog regularly. The news report adds: “The poll had a margin of error of plus or minus three percentage points at a 95% confidence level.” You can safely conclude that…
95% of all Gallup Poll samples like this one give answers within ±3% of the true population value.
The percent of the population who jog is certain to between 15% and 21%.
95% of the population jog between 15% and 21% of the time.
We can be 95% confident that the sample proportion is captured by the confidence interval.
If Gallup took many samples, 95% of them would find that 18% of the people in the sample jog.
The weights (in pounds) of three adult males are 160, 215, and 195. The standard error of the mean of these three weights is…
190
27.84
22.73
16.07
13.13
A 90% confidence interval for p, the proportion of all high school students at a local high school who participate in after school activities was found to be (0.743, 0.896).
1. Which of the following would be true about a 95% confidence interval constructed using the same data?
I. The interval would be wider because the critical z* would be larger.
II. The interval would be narrower because the critical z* would be smaller.
III. The interval would be wider because the standard error would be larger.
I only
II only
III only
I and III only
I and II only
One reason for using a t distribution instead of standard Normal curve to find critical values when calculating a level C confidence interval for a population mean is that…
Z can be used only for large samples.
Z requires that you know the population standard deviation ơ.
Z requires that you can regard your data as an SRS from the population.
Z requires that the sample size is at most 10% of the population size.
A z critical value will lead to a wider interval than t critical value.
What conditions are NOT necessary for a 95% t interval with a sample size of 9 to be valid?
The sample was selected randomly from the population of interest.
The population standard deviation is not known.
It is reasonable to assume that the population is approximately normal.
n*p-hat > 10 and n(1 - p-hat) > 10
All of the above are necessary conditions.
Assuming that the data came from a random sample from the population of interest, what other conditions must be met in order for the z interval to be an appropriate way to estimate a population proportion?
I. n ≥ 30 or the population is approximately normal.
II. The population size is at least 10 times greater than the sample size.
III. The population standard deviation is known
I and III
III and IV
II and IV
I, II and III
All of the above conditions must be met.
In preparing to construct a one-sample t interval for a population mean, suppose we are not sure if the population distribution is Normal. In which of the following circumstances would we not be safe constructing the interval based on an SRS of size 24 of the population?
A stemplot of the data is roughly bell-shaped.
A histogram of the data shows slight skewness.
A boxplot of the data has a large outlier.
The sample standard deviation is large.
A Normal probability plot of the data is fairly linear.
A radio talk show host with a large audience is interested in the proportion p of adults in his listening area who think the drinking age should be lowered to eighteen. To find this out, he poses the following question to his listeners: “Do you think that the drinking age should be reduced to eighteen in light of the fact that eighteen-year-olds are eligible for military service?” He asks listeners to phone in and vote “Yes” if they agree the drinking age should be lowered and “No” if not. Of the 100 people who phoned in, 70 answered “Yes”. Which of the following conditions for inference about a proportion using a confidence interval are violated?
I. The data are a random sample from the population of interest.
II. The population is at least 10 times as large as the sample.
III. n is so large that both n*p-hat & n(1 - p-hat) are at least 10.
I only
II only
III only
I and II only
I, II and III
Suppose we want a 90% confidence interval for the average amount spent on books by freshmen in their first year at a major university. The interval is to have a margin of error of $2. Based on last year’s book sales, we estimate that the standard deviation of the amount spent will be close to $30. The minimum sample size required is closest to…
25
30
608
609
865
A telephone poll of an SRS of 1234 adults found that 62% are generally satisfied with their lives. The announced margin of error for the poll was 3%. Does the margin of error account for the fact that some adults do not have telephones?
Yes. The margin of error includes all sources of error in the poll.
Yes. Taking an SRS eliminates any possible bias in estimating the population proportion.
Yes. The margin of error includes undercoverage but not nonresponse.
No. The margin of error includes nonresponse but not undercoverage.
No. The margin of error only includes sampling variability.
A Census Bureau report on the income of Americans says that with 90% confidence the median income of all U.S. households in a recent year was $57005 with a margin of error of ±$742. This means that…
90% of all households had incomes in the range of $57005 ± $742.
We can be sure that the median income for all households in the country lies in the interval $57005 ± $742
90% of the households in the sample interviewed by the Census Bureau had incomes in the interval $57005 ± $742.
The Census Bureau got the result $57005 ± $742 using a method that will capture the true median income 90% of the time when used repeatedly.
90% of all possible samples of this same size would result in a sample median that falls with $742 of $57005.
A city planner is comparing traffic patterns at two different intersections. He randomly selects 12 times between 6 am and 10 pm, and he and his assistant count the number of cars passing through each intersection during the 10-minute interval that begins at that time. He plans to test the hypothesis that the mean difference in the number of cars passing through the two intersections during each of those 12 times intervals is 0. Which of the following is the appropriate test of the city planner’s hypothesis?
Two-proportion
z-test
Two-sample
z-test
Matched pairs
t-test
One sample
t-test
Two sample
z-test
Different varieties of fruits and vegetables have different amounts of nutrients. These differences are important when these products are used to make baby food. Let μ1=mean amount carbs in variety 1 and μ2=mean amount carbs in variety 2 .
We wish to test if the two varieties are significantly different in their mean carbohydrate
content. Which of the following are the appropriate null and alternative hypotheses for this situation?
Ho: μ1−μ2=0 HA: μ1−μ2<0
Ho: μ1−μ2=0 HA: μ1−μ2>0
Ho: μ1−μ2=0 HA: μ1−μ2=0
Ho: x1−x2=0 HA: x1−x2<0
Ho: x1−x2=0 HA: x1−x2=0
Different varieties of fruits and vegetables have different amounts of nutrients. These differences are important when these products are used to make baby food. Let μ1=mean amount carbs in variety 1 and μ2=mean amount carbs in variety 2 . The conditions were met and a test was run with 5 samples to see if the two varieties are significantly different in their mean carbohydrate content. The test statistic = 2.011.
What is the appropriate conclusion at the .05 significance level?
The test provides convincing evidence that the carbohydrate content of variety 1 is higher
than variety 2.
The test provides convincing evidence that the carbohydrate contents of the two varieties
are equal.
We accept Ha: variety 1 has a higher carbohydrate content than variety 2.
We reject Ho: variety 1 has a higher carbohydrate content than variety 2.
We cannot reject Ho: we do not have convincing evidence that the carbohydrate contents
are different.
Popular wisdom is that eating presweetened cereal tends to increase the number of cavities in children. A sample of children was entered into a study and followed for several years. Each child was classified as a sweetened-cereal lover or a unsweetened cereal lover. At the end of the study, the amount of tooth damage was measured. The summary data is given. Assuming the necessary conditions for inference are met, which of the following is an approximate 95% confidence interval for the difference in the mean tooth damage?
1.21±2.262105+155
1.21±2.2621025+15225
1.21±2.1451025+15225
0±2.145105+1515
1.21±1.961005+22515
You are constructing a 90% confidence interval for the difference of means from simple random samples from two independent populations. The sample sizes are n1= 6 and n2 =14. You draw dot plots of the samples to check the normality condition for two-sample t-procedures. Which of the following descriptions of those dot plots would suggest that it is safe to use t-procedures?
I. The dot plot of sample 1 is roughly symmetric, while the dot plot of sample 2 is moderately skewed left. There are no outliers.
II. Both dot plots are roughly symmetric. Sample 2 has an outlier.
III. Both dot plots are strongly skewed to the right. There are no outliers.
I only
II only
I and II
I, II, and III
none of the above
Which of the following is not a required condition for performing a t-test about an unknown population mean μ ?
The data can be viewed as a simple random sample from the population of interest.
The population standard deviation σ is known.
The population distribution is Normal or the sample size is large (say n > 30).
The data represent n independent observations.
All four of the above are required conditions.
An appropriate 95% confidence interval for μ has been calculated as ( − 0.73, 1.92) based on n = 15 observations from a population with a Normal distribution. If we wish to use this confidence interval to test the hypothesis
Ho: μ = 0 against Ha: μ ≠0,
which of the following is a legitimate conclusion?
Reject Ho at the
α = 0.05 level of significance.
Fail to reject Ho at the α = 0.05 level of significance.
Reject Ho at the
α = 0.10 level of significance.
Fail to Reject Ho at the α = 0.10 level of significance.
We cannot perform the required test since we do not know the value of the test statistic.
Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. Net weights actually vary slightly from bag to bag and are Normally distributed with mean μ . A representative of a consumer advocacy group wishes to see if there is any evidence that the mean net weight is less than advertised and so intends to test the hypotheses
Ho :μ =14 Ha :μ <14
A Type I error in this situation would mean
concluding that the bags are being underfilled when they actually aren’t
concluding that the bags are being underfilled when they actually are.
concluding that the bags are not being underfilled when they actually are.
concluding that the bags are not being underfilled when they actually aren’t.
none of these
A machine is designed to dispense at least 12 ounces of a beverage into a bottle. To test whether the machine is working properly, a random sample of 50 bottles was selected and the mean number of ounces for the 50 bottles was computed. A test of the hypotheses H0 : µ = 12 versus Ha: µ < 12 was conducted, where µ represents the population mean number of ounces of the beverage dispensed per bottle by the machine. The p-value for the test was 0.08. Which of the following is the most appropriate conclusion to draw at the significance level of α = 0.05?
Because the p-value is greater than the significance level, there is convincing evidence that the population mean number of ounces dispensed into a bottle is 12 ounces.
Because the p-value is greater than the significance level, there is convincing evidence that the population mean number of ounces dispensed into a bottle is less than 12 ounces.
Because the p-value is greater than the significance level, there is not convincing evidence that the population mean number of ounces dispensed into a bottle is less than 12 ounces.
Because the p-value is less than the significance level, there is convincing evidence that the population mean number of ounces dispensed into a bottle is 12 ounces.
Eight percent of the bottles will be filled with less than 12 ounces.
Makers of a new pain-relieving medication claim that it relieves chronic pain faster than the current top-selling pain reliever on the market. A double-blind experiment was conducted in which 10 people who experience chronic pain were randomly selected to take either the new or the current medication. Each of the 10 people recorded the time, in minutes, from taking the medication until pain relief. After an appropriate time period, each of the 10 people took the other medication and recorded the time from taking the medication until pain relief. The medication each person took first was randomly determined, and because both medications look the same, the people in the study did not know which medication was taken first. The table below shows summary statistics for the results. Which of the following values is closest to the p-value of the appropriate t-test?
0.1802
0.3604
0.4230
0.5770
0.8198
Which of the following best describes a Type I error?
The null is true, but we mistakenly reject it.
The null is false and we reject it.
The null is false, but we fail to reject it.
The null is true but we fail to reject it.
The null is true, and we fail to reject it.
The null hypothesis is represented by:
Ha
Ho
t*
HP
μ
The null hypothesis always contains a(an):
< or >
=
>
= or >
≠
Which of the following best describes a type II error?
The null is true, but we mistakenly reject it.
The null is false and we reject it.
The null is false, but we fail to reject it.
The null is true but we fail to reject it.
Te null is false, and we reject it.
When conducting a significance test for the difference in proportions, why do we pool the data when finding standard error?
Because we like to swim
Because we assume p1 = p2 in Ho
Because the sample sizes are always equal
To be safe and make sure we don't underestimate the standard error
Because we don't the standard deviation.
How to interpret the coefficient -0.059?
When the sale price decrease by $1, the corresponding mileage will increase by 0.059 miles.
When the sale price increase by $1, the corresponding mileage must increase by 0.059 miles.
When the mileage increases by 1 mile, the sale price will decrease $0.059.
When the mileage increases by 1 mile, the sale price will increase $0.059.
Predict the sales price for a car with a mileage of 100000 miles.
$16529
$10570
$5916.47
$16529
How is the the quality of this regression equation?
The goodness of fit of the regression is bad because the R square is 0.539. i.e. 53.9% variation is explained by the linear regression.
The goodness of fit of the regression is not too bad because the multiple R is 0.734, i.e. 73% variation is explained by the regression.
The goodness of fit of the regression is good because the multiple R is 0.734, i.e. 73.4% of the variation is explained by the linear regression.
The goodness of fit of the regression is good because the R square is 0.539, i.e. 53.9% of the variation is explained by the linear regression
The Gallup Poll interviews 1600 people. Of these, 18% say that they jog regularly. The news report adds: “The poll had a margin of error of plus or minus three percentage points at a 95% confidence level.” You can safely conclude that
95% of all Gallup Poll samples like this one give answers within ± 3% of the true population value.
95% of all Gallup Poll samples like this one give answers within ± 3% of the true population value.
95% of all Gallup Poll samples like this one give answers within ± 3% of the true population value.
we can be 95% confident that the sample proportion is captured by the confidence interval.
if Gallup took many samples, 95% of them would find that 18% of the people in the sample jog.
