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WorksheetsReview for Spring Calculus Final 2024
Total questions: 114
Worksheet time: 10hrs 30mins
f(x) = 1 - x2
y = 32x+5
y=4ex²
y=11x²
f(x)= ex
f ' (x) = ?
ex
xex
x
1
f(x)= Ln(x)
f ' (x) = ?
Log(x)
-1/(xLn(x))
1/(xLn(x))
1/x
f(x)= x3+8x
f ' (x) = ?
3x2
3x2+8
2x3+8
2x3
f(x)= Ln(9x2)
f ' (x) = ?
2/x
18x/9
x/2
2
f(x)= ex^2
f ' (x) = ?
e2x
2ex^2
2xex^2
2xe2x
find y' for y= (2x+1)10
10(2x+1)9
20(2x-1)9
20(2x+1)10
20(2x+1)9
Evaluate the limit.
x→2lim x2−4x3−8
3
4
6
12
Which of the following velocity time graphs matches the position time graph above?
Which of the following velocity time graphs matches the position time graph above?
Which of the following velocity time graphs matches the position time graph above?
The slope of the velocity-time graph tells us the
acceleration
displacement
velocity
direction of travel
The slope of the position-time graph tells us the
acceleration
displacement
velocity
direction of travel
What is the acceleration of the object at time t = 2 s?
Find the average velocity from t = 3 to t = 5.
v (t) > 0 means
the particle is moving to the right
the particle is speeding up
the particle has positive position
the particle is at rest
What does this calculate?
Average Rate of Change of f over [a,b]
Average Value of f
Intermediate Value Theorem
L'Hopital's Rule for limits
The Mean Value Theorem applies to f(x) = 3x - x2 on the interval [2, 5]. Find the value of x where the slope of the tangent line is equal to the slope of the secant line
2
-4
3.5
-2
Which of these sums up the Mean Value Theorem (MVT)?
f′(c)=b−af(b)−f(a)
f(c)=b−af(b)−f(a)
f(c)=b−af′(b)−f′(a)
f′(c)=b−af′(b)−f′(a)
Which of these is NOT a hypothesis of the Mean Value Theorem (MVT)?
A closed interval
A differentiable function
A continuous function
A twice-differentiable function
If f and g are inverses what is g'(x)?
g′(x)=f′(g(x))1
g′(x)=f′(x)1
g′(x)=f′(x)−1
g′(x)=f′(g(x))−1
Tangent line formula.
y−f(x1)=f′(x1)(x−x1)
y=f′(x1)(x−x1)
y−f(y1)=f′(x1)(x−x1)
y=f(x1)(x−x1)
The fundamental theorem of calculus.
∫abf(x)=F(b)−F(a) where F is the antiderivative
∫abf(x)=f′(b)−f′(a)
∫abF(x)=f(b)−f(a) where F is the antiderivative
∫abF(x)=f′(b)−f′(a) where F is the antiderivative
The fundamental theorem of calculus.
dxd∫0xf(t)dt=f(x)
dxd∫0xf(t)dt=F(x) where F is the antiderivative
dxd∫0xF(t)dt=f(x) where F is the antiderivative
dxd∫0xf(t)dt=f′(x)
Volume using discs revolving around horizontal line.
π∫x=ax=b(top −bottom)2dx
π∫x=ax=b(top −bottom)dx
∫x=ax=b(top −bottom)2dx
∫x=ax=b(top −bottom)dx
Volume using discs revolving around vertical line.
π∫y=ay=b(right −left)2dy
π∫y=ay=b(right −left)dy
∫y=ay=b(right −left)2dy
∫y=ay=b(right −left)dy
Volume using washers revolving around horizontal line.
π∫x=ax=bR2−r2 dx
π∫x=ax=b(R−r)2 dx
∫x=ax=b(R−r)2dx
∫x=ax=bR2 −r2 dx
Volume using washers revolving around vertical line.
π∫y=ay=bR2−r2 dy
π∫y=ay=b(R−r)2dy
∫y=ay=b(R−r)2dy
∫y=ay=bR2−r2 dy
What is the integrand when finding the volume of a solid with cross sections of semicircles?
8πL2
4πL2
2πL2
πL2
How do you calculate the "L" in a cross sectional volume problem when perpendicular to the x-axis?
L=right−left
L=top−bottom
L=right2−left2
L=top2−bottom2
g(x)=2x3-3x2
f(x)=32x3−6x2+16x+14
Find the critical numbers of f(x). Select ALL that apply
x=2
x=0
x= -4
x= -2
x = 4
What is the location of the absolute maximum for the graphed function?
x = 1
x = 3
x = 4
x = 5
Does Not Exist
How many extrema are there in this graph?
2 max, 2 min
3 max, 2 min
2 man, 3 min
3 increasing intervals, 2 decreasing intervals
2 increasing intervals, 3 decreasing intervals
What is the relative max?
x = 0
x = -2.55
(-∞, ∞)
None
Find the point(s) of inflection (if it exists) of the graphed function.
No point of inflection
Points b and g
Points b, f and g
Points a, b, c, d, e, f, g, and h
Points a, c, e, f and h
Find the point(s) of inflection (if it exists) of the graphed function.
No point of inflection
Points K, R, and S.
Points K and S
Points P, Q, K, R, S, and T
Points Q and T
Discuss the concavity and the point(s) of inflection (if any) of the function:
Concave up in (−∞,1) , Concave down in . And the point of inflection at x = 1
Concave down in (−∞,1) , Concave up in . And the point of inflection at x = 1
Concave down in (−∞,∞) . with no point of inflection.
Concave up in (1,∞) . with no point of inflection.
Find the point(s) of inflection (if it exists) of the function:
Select ALL the correct answer(s).
No point of inflection
At x = 2
At x = 5
At x = ∞
At x = 3.5
Discuss the concavity and the point(s) of inflection (if any) for the function
Concave down in (0,∞) Concave up in ,. And Point of Inflection at x = 0
Concave up in (−∞,0) Concave down in ,. And Point of Inflection at x = 0
Concave down in (−∞,0) with no inflection point.
Concave up in (0,∞) and . with no inflection point.
Concave up in (−∞, ∞) with no inflection point.
Discuss the concavity and point(s) of inflection (if any) for the function:
Concave up in (−∞,−2) and , Concave down in (-2, 2). And points of inflection at x = -2 and 2
Concave down in (−2, 2) and , Concave up in (-2, 2). And points of inflection at x = -2 and 2
Concave down in (4,∞) ,With no points of inflection.
Concave up in (−∞,∞) ,With no points of inflection.
Find the right-hand Riemann Sum, with three sub-intervals indicated by the table.
28
16
34
21
x: 0 2 4 6 8 10 12
f(x): 7 11 20 25 18 14 9
x: 0 1 2 3 4 5 6
f(x): 12 10 9 11 13 16 18
x2
∫6x4+3x2+5x +5 dx
5x5+3x4+5x2 +5x
5x5+3x3+5x2 +5x
56x5+x3+5x2 +5x +c
56x5+x3+25x2 +5x +c
dy/dx = 2x/e2y find the general solution
y = ln (2x/2 + C)
2
y = ln(2x/2)+c
y = e2x+c
y = mx+b
dy/dx= x √y
Find the general solution
√y = ln|4x| + c
√y = (x)-1 + c
2y1/2 = ln|x| + c
1/2y1/2 = ln|x| + c
Determine the value of "c" that satisfies the differential equation dxdy=y+2x+1 if the curve goes through the point (0, -1).
5/2
-3/2
-1/2
1
Which of the following is the solution to the differential equation dxdy=yx2 with the initial condition y(3) = -2?
y=−2e(−9+3x3)
y=32x3
y=32x3−14
y=−32x3−14
Solve the following differential equations:
dxdy=cosy1
siny=1+C
siny=x+C
−siny=2x2+C
siny=0+C
Solve the following differential equations:
dxdy=ex
1=ex+C
y=2ex+C
y=ex+C
0=ex+C
Find the area of the region enclosed by the lines and curves.
y = 3x + 4 and y = x² + 4
9
93/2
9/2
18
Write the integral that can be used to find the region bounded by x = -3y² + 4 and x = y³.
